An isosceles triangle has two long sides and one short side.the short side is half the length of along side. If the perimeter of the triangle is 15 cm, the length of the short side.
short side length=s
so
perimeter=s + 2 s + 2 s = 5 s = 15
s = 15 / 5
Let the short side be=X. PERIMETER=X +2X+ 2X=5X=15. 15/5
Well, well, well, looks like we have ourselves an isosceles triangle with some mysterious side lengths! Let's put on our detective hats and solve this puzzle!
Let's call the length of the short side "x" (because why not?). And since the long sides are twice the length of the short side, we'll call them "2x".
Now, the perimeter of a triangle is just the sum of all its sides. In this case, we have two long sides and one short side. So, we can write an equation to represent the perimeter of this triangle:
Perimeter = Short side + Long side + Long side
Plugging in the given values, we get:
15 cm = x + 2x + 2x
Simplifying the equation, we get:
15 cm = 5x
Now, to solve for x, we just need to divide both sides of the equation by 5:
15 cm / 5 = 5x / 5
3 cm = x
Hence, the length of the short side is 3 cm.
And there you have it! The short side of our isosceles triangle is 3 cm. Mystery solved!
To find the length of the short side of an isosceles triangle given that the two longer sides are equal and the perimeter is 15 cm, we can follow these steps:
Step 1: Let's represent the length of the long side as "x" cm.
Step 2: According to the problem, the short side is half the length of a long side, so its length can be represented as "x/2" cm.
Step 3: The perimeter of a triangle is the sum of the lengths of all its sides. In this case, the perimeter is given as 15 cm.
Therefore, we can set up the equation: x + x + (x/2) = 15
Step 4: Now, let's simplify the equation.
Combining the like terms on the left side, we get: 2x + (x/2) = 15
Multiplying both sides by 2 to eliminate the fraction, we have: 4x + x = 30
Combining like terms on the left side again, we get: 5x = 30
Step 5: To isolate x, the coefficient of x, we divide both sides of the equation by 5.
x = 30/5
Simplifying, we find: x = 6
Step 6: Now that we have the value of x, we can find the length of the short side by substituting it into the equation: x/2 = 6/2
This simplifies to: x/2 = 3
Thus, the length of the short side is 3 cm.
L = 2 s
L + L + s = 15 cm ... 2s + 2s + s = 15 cm ... s = ?