1. Which equation represents the axis of symmetry of the function y = –2x² + 4x –6? (1 point)
y = 1
x = 1
x = 3
x = –3
btw this is for Algebra 1B unit 4 lesson 2
i already did the quick check but i want yall to get them right so the answers are below:)
Well, it is a parabola and y goes to infinity as x gets large + or -
(opens upward)
let's see where the zeros are
Let me see where the zeros are
-2 x^2 + 4 x -6 = 0
x^2 - 2 x + 3 = 0
x = (2 +/- sqrt .... etc ) /2
x = 1 +/-sqrt ........
so symmetric about x = 1
1. B
2. A
3. D
4. B
5. D
6. B
7. D
8. C
Hope i helped :)
To find the equation that represents the axis of symmetry of the function, we need to use the formula x = -b/2a, where a, b, and c are the coefficients of the quadratic equation in the form ax² + bx + c.
In this case, the equation y = -2x² + 4x - 6 has a coefficient of a = -2 and b = 4. Plugging these values into the formula, we get:
x = -4/(2*(-2))
x = -4/(-4)
x = 1
Therefore, the equation that represents the axis of symmetry of the function y = -2x² + 4x - 6 is x = 1.
To find the equation that represents the axis of symmetry of the function y = -2x² + 4x - 6, we can use the formula x = -b/2a.
Here, the equation is in the form y = ax² + bx + c, where a = -2, b = 4, and c = -6.
Substituting these values into the formula x = -b/2a, we get:
x = -4 / (2 * -2)
Simplifying the expression:
x = -4 / -4
x = 1
Therefore, the equation that represents the axis of symmetry is x = 1.