a Carbon monoxide is 43% carbon by mass; nitrous oxide is 30% nitrogen by mass. For both gases, the remainder is oxygen. In a mixture containing 5g of each gas, what is the mass of oxygen present?
b A 5g sample of carbon monoxide is mixed with 4g of nitrous oxide and 3 g of sulfur dioxide. Sulfur dioxide is 50% sulfur by mass, the balance is oxygen. What is the percentage by mass of oxygen and of sulfur present in the mixture? Use the mass compositions given in part a.
a. Well, we know that carbon monoxide is 43% carbon by mass and nitrous oxide is 30% nitrogen by mass. So, we can calculate the mass of carbon in the 5g of carbon monoxide as (5g) * (0.43) = 2.15g. Similarly, the mass of nitrogen in the 5g of nitrous oxide would be (5g) * (0.3) = 1.5g.
Since the remainder is oxygen, let's calculate the total mass of carbon dioxide and nitrous oxide. Carbon monoxide has a mass of 5g and nitrous oxide has a mass of 5g, so the total mass of the gases is 5g + 5g = 10g.
Therefore, the mass of oxygen in the mixture would be the total mass of the gases (10g) minus the mass of carbon dioxide (2.15g) minus the mass of nitrous oxide (1.5g). This comes out to be 10g - 2.15g - 1.5g = 6.35g.
So, the mass of oxygen present in the mixture is 6.35g.
b. Alrighty, let's tackle this one step at a time. We know that the carbon monoxide has a mass of 5g, so the mass of carbon in it would be 5g * 0.43 = 2.15g.
Now, let's figure out the mass of nitrogen in the nitrous oxide. The nitrous oxide itself has a mass of 4g, and since it is 30% nitrogen by mass, the mass of nitrogen would be 4g * 0.3 = 1.2g.
Moving on to sulfur dioxide, we have a mass of 3g. We know that sulfur dioxide is 50% sulfur by mass, so the mass of sulfur in it would be 3g * 0.5 = 1.5g.
For the percentage by mass of oxygen in the mixture, we need to find the total mass of the gases first. The carbon monoxide has a mass of 5g, nitrous oxide has a mass of 4g, and sulfur dioxide has a mass of 3g. Adding these up gives us a total mass of 5g + 4g + 3g = 12g.
Now, taking into account the mass of carbon dioxide (2.15g), nitrous oxide (1.2g), and sulfur dioxide (1.5g), we can say that the mass of oxygen in the mixture is 12g - 2.15g - 1.2g - 1.5g = 7.15g.
So, the percentage by mass of oxygen in the mixture is (7.15g / 12g) * 100%, which is approximately 59.6%.
As for the percentage by mass of sulfur, it would be (1.5g / 12g) * 100%, which is about 12.5%.
Hope that clears it up for you!
a) To find the mass of oxygen present in the mixture, we first need to find the mass of carbon and nitrogen in the mixture.
Given that carbon monoxide is 43% carbon by mass and nitrous oxide is 30% nitrogen by mass, the remaining percentage represents the amount of oxygen in each gas.
For carbon monoxide:
Mass of carbon = 43% of 5g = 0.43 * 5g = 2.15g (rounded to 2 decimal places)
For nitrous oxide:
Mass of nitrogen = 30% of 5g = 0.3 * 5g = 1.5g (rounded to 2 decimal places)
Since the remainder is oxygen, the mass of oxygen can be calculated as the total mass of the mixture minus the sum of the mass of carbon and nitrogen.
Mass of oxygen = Total mass - (Mass of carbon + Mass of nitrogen)
Mass of oxygen = 5g - (2.15g + 1.5g)
Mass of oxygen = 5g - 3.65g
Mass of oxygen = 1.35g
Therefore, the mass of oxygen present in the mixture is 1.35 grams.
b) To find the percentage by mass of oxygen and sulfur in the mixture, we need to use the given mass compositions from part a.
From part a, we know that in the mixture:
Mass of carbon = 2.15g
Mass of nitrogen = 1.5g
Mass of oxygen = 1.35g
For sulfur dioxide:
Mass of sulfur = 50% of 3g = 0.5 * 3g = 1.5g (rounded to 2 decimal places)
Since the remainder is oxygen, the mass of oxygen can be calculated as the total mass of the mixture minus the mass of sulfur.
Mass of oxygen = Total mass - Mass of sulfur
Mass of oxygen = (5g + 4g) - 1.5g
Mass of oxygen = 9g - 1.5g
Mass of oxygen = 7.5g
To find the percentage by mass of oxygen and sulfur:
Percentage of oxygen = (Mass of oxygen / Total mass) * 100
Percentage of oxygen = (7.5g / (5g + 4g + 3g)) * 100
Percentage of oxygen = (7.5g / 12g) * 100
Percentage of oxygen = 62.5%
Percentage of sulfur = (Mass of sulfur / Total mass) * 100
Percentage of sulfur = (1.5g / (5g + 4g + 3g)) * 100
Percentage of sulfur = (1.5g / 12g) * 100
Percentage of sulfur = 12.5%
Therefore, the percentage by mass of oxygen in the mixture is 62.5%, and the percentage by mass of sulfur in the mixture is 12.5%.
a) To find the mass of oxygen present in the mixture, we first need to determine the mass of carbon in carbon monoxide and the mass of nitrogen in nitrous oxide.
Given that carbon monoxide is 43% carbon by mass, we can calculate the mass of carbon in carbon monoxide as follows:
Mass of carbon in carbon monoxide = 43% of 5g
= (43/100) * 5g
= 2.15g
Similarly, since nitrous oxide is 30% nitrogen by mass, we can calculate the mass of nitrogen in nitrous oxide as follows:
Mass of nitrogen in nitrous oxide = 30% of 5g
= (30/100) * 5g
= 1.5g
Now, to find the mass of oxygen in the mixture, we subtract the sum of the masses of carbon and nitrogen from the total mass of the mixture:
Mass of oxygen = Total mass of the mixture - (Mass of carbon + Mass of nitrogen)
= 5g - (2.15g + 1.5g)
= 5g - 3.65g
= 1.35g
Therefore, the mass of oxygen present in the mixture is 1.35g.
b) To find the percentage by mass of oxygen and sulfur in the mixture, we need to consider the masses of carbon monoxide, nitrous oxide, and sulfur dioxide provided.
From part a, we know that the mass composition of carbon monoxide is 43% carbon, 57% oxygen, and no nitrogen. Similarly, the mass composition of nitrous oxide is 30% nitrogen and 70% oxygen.
Since carbon monoxide is the only substance that contains carbon, we can determine the mass of carbon present in the mixture as:
Mass of carbon = Mass of carbon monoxide
= 5g
Now, we can calculate the mass of oxygen present in the mixture by considering the mass composition of carbon monoxide and nitrous oxide:
Mass of oxygen = (Mass of carbon monoxide * Percentage of oxygen in carbon monoxide) + (Mass of nitrous oxide * Percentage of oxygen in nitrous oxide)
= (5g * 57%) + (4g * 70%)
= (5g * 0.57) + (4g * 0.7)
= 2.85g + 2.8g
= 5.65g
Next, we need to calculate the mass of sulfur in sulfur dioxide by considering its mass composition:
Mass of sulfur in sulfur dioxide = 50% of 3g
= (50/100) * 3g
= 1.5g
Finally, we can find the percentages by mass of oxygen and sulfur in the mixture as:
Percentage of oxygen = (Mass of oxygen / Total mass of the mixture) * 100%
= (5.65g / (5g + 4g + 3g)) * 100%
= (5.65g / 12g) * 100%
= 47.08%
Percentage of sulfur = (Mass of sulfur / Total mass of the mixture) * 100%
= (1.5g / (5g + 4g + 3g)) * 100%
= (1.5g / 12g) * 100%
= 12.5%
Therefore, the percentage by mass of oxygen in the mixture is 47.08% and the percentage by mass of sulfur is 12.5%.