Mark is building a scale model of his car as shown in the diagram. The actual car has a height of 10 feet and the model has a height of 1 foot at the same place.
A. What is the actual length of the car? Show your work.
B. Mark has model wheels with a diameter of 6 inches. If the actual wheel radius is 2.25 feet, will they be in proportion with his model? Justify your answer.
A- 12.5
(I used the formula a.bc X de = f X g = ft of car)
1.25x10=12.5X1=12.5ft
is Tay right?
someone help who is rightðŸ˜
nvm guys Tay is right🙂
A. To find the actual length of the car, we can use the concept of scale factor. The scale factor is the ratio of the length of the model to the length of the actual object. In this case, the scale factor is 1:10 since the model height is 1 foot and the actual height is 10 feet.
Let's represent the actual length of the car as "L" (in feet). Using the scale factor, we can create the equation:
1 foot (model height) / 10 feet (actual height) = 1 foot (model length) / L feet (actual length)
Cross multiplying, we get:
1 * L = 10 * 1
L = 10 feet
Therefore, the actual length of the car is 10 feet.
B. To check if the model wheels are in proportion with the actual wheels, we need to compare the proportions of their radii.
The ratio of the model wheel radius to the actual wheel radius should be the same as the scale factor used for the height, which is 1:10. Let's calculate the ratio:
Model wheel radius: 6 inches = 0.5 feet
Actual wheel radius: 2.25 feet
Now, we can set up the proportion using these values:
0.5 feet (model wheel radius) / 2.25 feet (actual wheel radius) = 1 (model scale factor) / 10 (actual scale factor)
Cross multiplying, we get:
0.5 * 10 = 2.25 * 1
5 = 2.25
Since 5 does not equal 2.25, the model wheels are not in proportion with the actual wheels.
clearly the scale is 1:10
(A) ??
(B) no