# Geometry B U2 L3 Proving That a Quadrilateral...

Geometry B U2 L3 Proving That a Quadrilateral Is a Parallelogram Answers

1. Complete this statement: A polygon with all sides the same length is said to be ______.

2. A road sign is in the shape of a regular heptagon. What is the measure of each angle on the sign? Round to the nearest tenth.

3. In the figure, the horizontal lines are parallel and AB=BC=CD. Find the measure of JM. The diagram is not drawn to scale.

4. Find the sum of the measures of the interior angles of the figure.

5. Find the value of x. The diagram is not drawn to scale.
Answer - C. x = 99

6. The sum of the measures of two exterior angles of a triangle is 264°. What is the measure of the third exterior angle?

7. How many sides does a regular polygon have if each exterior angle measures 72°?

8. What are the missing reasons in the proof?
Answers - 3. definition of parallelogram
4. alternate interior angles theroem
5. reflexive property of congruence
6. ASA

9.Based on the information in the diagram, determine whether the figure is a parallelogram. If so, select the answer with the correct justification.
Answer - D. Yes, both pairs of opposite sides are congruent.

10. Complete the two-column proof.
Answers - 2. SV // TU
3. SV // TU
7. Corresponding part of congruent triangle
8. Definition of parallelogram.

100% Hope this helps! Btw, this is only the first half of the quiz. The second half is different for everyone.

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1. But just in case some people have the same "part 2 quiz" questions that I did, here they are...

1. Find the values of the variables x,y, and z in the parallelogram. The diagram is not drawn to scale. (diagram shows a tilted square with 33 in top left corner, 109 in top right, z in bottom left, and x and y in bottom right.)

Explanation -
x=33 (alternate angles)
33+109+y=180
142+y=180
y=180-142
y=38
z=109

2. In parallelogram DEFG, DH = x + 1, HF = 3y, GH = 3x − 4, and HE = 5y + 1. Find the values of x and y. The diagram is not drawn to scale.
DH = HF
x + 1 = 3y
y = (x + 1) ⁄ 3

GH = HE
3x – 4 = 5y + 1
y = (3x – 5) ⁄ 5

y = y
(x + 1) ⁄ 3 = (3x – 5) ⁄ 5
5x + 5 = 9x – 15
4x = 20
x = 5

y = (x + 1) ⁄ 3
y = (5 + 1) ⁄ 3
y = 2

3. If ON = 8x − 8, LM = 7x + 4, NM = x − 5, and OL = 3y − 6, find the values of x and y for which LMNO must be a parallelogram. The diagram is not drawn to scale.
ON = LM
8x-8 = 7x+4
x = 12

OL = NM
3y-6 = x-5
3y-6 = 12-5
3y = 13
y = 13/3

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2. No name is 100 percent right for part 1 of quiz 👍

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3. On the 2nd part of the test on question 2, Instead of setting the values equal to each other we would set them equal to 180 right?

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4. I correct myself

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5. I am wrong

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6. no name is right on test one i had the same answers as them for test two so

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7. You're not that guy pal, you're not that guy.

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8. @no name, bro thank you so much

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