sarah rolls a fair dice and adds the results from each
work out the probability of getting a total more than two
there are 36 possible outcomes ... 6 * 6
only one outcome is not more than two ...1 & 1
... so 35 outcomes are more than two
To calculate the probability of getting a total more than two when rolling a fair dice, we need to determine the number of favorable outcomes and the total number of possible outcomes.
The total number of possible outcomes when rolling a fair dice is 6, as there are 6 sides with numbers from 1 to 6.
Now, let's consider the favorable outcomes.
There are several ways to get a total more than two when rolling two dice:
1. Roll a 3: This can occur in two ways: (1, 2) or (2, 1).
2. Roll a 4: This can occur in three ways: (1, 3), (3, 1), or (2, 2).
3. Roll a 5: This can occur in four ways: (1, 4), (4, 1), (2, 3), or (3, 2).
4. Roll a 6: This can occur in five ways: (1, 5), (5, 1), (2, 4), (4, 2), or (3, 3).
5. Roll a 7: This can occur in six ways: (1, 6), (6, 1), (2, 5), (5, 2), (3, 4), or (4, 3).
6. Roll an 8: This can occur in five ways: (2, 6), (6, 2), (3, 5), (5, 3), or (4, 4).
7. Roll a 9: This can occur in four ways: (3, 6), (6, 3), (4, 5), or (5, 4).
8. Roll a 10: This can occur in three ways: (4, 6), (6, 4), or (5, 5).
9. Roll an 11: This can occur in two ways: (5, 6) or (6, 5).
10. Roll a 12: This can occur in one way: (6, 6).
Adding up all these favorable outcomes, we get a total of 36.
Therefore, the probability of getting a total more than two when rolling a fair dice is:
Favorable Outcomes / Total Outcomes = 36 / 6
Simplifying, we get:
6 / 6 = 1
So, the probability of getting a total more than two when rolling a fair dice is 1, or 100%.
To calculate the probability of getting a total more than two when rolling a fair dice, we need to consider the possible outcomes and determine how many of those outcomes meet the given condition.
First, let's list all the possible outcomes when rolling a fair dice:
1. The dice shows 1
2. The dice shows 2
3. The dice shows 3
4. The dice shows 4
5. The dice shows 5
6. The dice shows 6
Now, let's calculate the probabilities of getting each outcome. Since the dice is fair, each outcome has an equal probability of occurring, which is 1/6.
To find the probability of getting a total more than two, we need to identify the outcomes that meet this condition. In this case, a total more than two means any outcome greater than or equal to three. So, we need to count the outcomes "3," "4," "5," and "6."
There are four outcomes out of a total of six that meet this condition. Therefore, the probability of getting a total more than two is 4/6, which simplifies to 2/3.
To summarize:
- The probability of getting a total more than two when rolling a fair dice is 2/3, or approximately 0.6667.