Chemistry

If the Fe2+(aq) + 2e---> Fe(s) was used as a reference for the electrode potential table instead of the standard hydrogen half cell what would the potential of the following half cell be?
Ni2+(aq) + 2e---> Ni(s)

A) -0.19 V
B) -0.71 V
C) +0.19 V
D) +0.71 V

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
  1. My tables may not be the same as your tables. I'll use mine and you can check yours. When you post questions like this you should ALWAYS LOOK UP THE VALUES in your text/notes. The best way to do this type problem is to draw a diagram. That's difficult to do on this site but here's the best I can do. With reference to H2 the diagram shows:
    2H^+ + 2e ---> H2..................0
    Ni^2+ + 2e ==> Ni.................-0.23
    Fe^2+ + 2e ==> Fe................-0.41
    What I've done is looked up IN MY REFERENCES the reduction potential for H, Ni and Fe. I've arranged them in order. So now if Fe is the standard you can see that the Ni potential is ABOVE Fe; therefore, Ni potential will be + the difference. The difference is 0.41-0.23 = 0.18 and it is 0.18 ABOVE Fe so it will be 0.18 referenced to Fe potential.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chemistry

    What would the potential of a standard hydrogen (S.H.E.) electrode be if it was under the following conditions? [H+] = 0.38 P(H2) = 3.8 T = 298 K

  2. General Chemestry

    A galvanic (voltaic) cell consists of an electrode composed of chromium in a 1.0 M chromium(II) ion solution and another electrode composed of gold in a 1.0 M gold(III) ion solution, connected by a salt bridge. Calculate the

  3. chemistry

    How do you calculate the theoretical cell voltage? 1) Zn|Zn^+2 (1M)| Cu|Cu^+2 (1M) okay so by looking at example this example Calculate the emf (voltage) for the following reaction: Zn(s) + Fe2+ → Zn2+ + Fe(s) Write the 2 half

  4. AP CHEMISTRY

    A solution is prepared in which a trace or small amount of Fe2+ is added to a much larger amount of solution in which the [OH-] is 1.0 x 10^-2 M. Some Fe(OH)2 precipitates. The value of Ksp for Fe(OH)2 = 8.0 x10^-10. A. Assuming

  1. Chemistry

    3Fe2+(aq) + 2Al(s) --> 3Fe(s) + 2Al3+(aq) Which of the following statements is true about Fe2+? 1.Fe2+ is losing electrons. 2.Fe2+ is oxidized. 3.Fe2+ is the oxidizing agent. 4.Fe2+ is the reducing agent.

  2. Chemistry

    calculate cell potential at 25C for: 3Fe3+(aq) + AL(s)= 3Fe2+(aq)+ Al3+ (aq) if Fe3+ = 0.300 M, Fe2+ = 0.150M Al3+ = 0.300M. The standard reduction potentials are as follows: Fe3+ (aq) + e- = Fe2+ (aq) Al3+ (aq) + 3e-=Al (s) Eo =

  3. AP Chem

    An electrochemical cell consists of a nickel metal electrode immersed in a solution with [Ni2+] = 1.0 M separated by a porous disk from an aluminum metal electrode. (a) What is the potential of this cell at 25°C if the aluminum

  4. chemistry

    To what pH should you adjust a standard hydrogen electrode to get an electrode potential of -0.124V V ? (Assume that the partial pressure of hydrogen gas remains at 1 atm.)

  1. Chemistry

    A galvanic (voltaic) cell consists of an electrode composed of aluminum in a 1.0 M aluminum ion solution and another electrode composed of fold in a 1.0 M gold (III) ion solution connected by a salt bridge. Calculate the standard

  2. Chemistry ASAP

    Using a table of standard electrode potentials (such as the one in your textbook), calculate the standard cell potential for a cell made by placing a zinc electrode in a Zn2+(aq) solution which is connected by an electrolyte to a

  3. Chemistry

    A zinc-copper battery is constructed as follows at 25°C. Zn|Zn^2+ (0.15 M)||Cu2+(3.00 M)|Cu The mass of each electrode is 200. g. a) Calculate the cell potential when this battery is first connected. - i got this to be 1.14V b.)

  4. Chemistry/Redox Reactions

    An electrochemical cell consists of a nickel metal electrode immersed in a solution with [Ni2+] = 1.0 M separated by a porous disk from an aluminium metal electrode immersed in a solution with [Al3+] = 1.0 M. Sodium hydroxide is

View more similar questions or ask a new question.