The right arrow symbol used to show the transition from a point to its image after a transformation is not contained within the Equation Editor. If such a symbol is needed, type "RightArrow." For example: P(0, 0) RightArrow P′(1, 2).
Triangle ABC has coordinates
A
(
1
,
4
)
;
B
(
3
,
−
2
)
;
and
C
(
4
,
2
)
.
Find the coordinates of the image
A
'
B
'
C
'
after a reflection over the x-axis.
It would of have NOT been a good idea to draw a sketch. You can’t even post anything on here. What’s the use of making a sketch if you can’t even post it
Geessshhh, how about just like this instead of all that gibberish:
Triangle ABC has coordinates
A(1,4); B(3,-2); and C(4,2).
Find the coordinates of the image
A'B'C' after a reflection over the x-axis.
Would it not have been a good idea to make a sketch of what would happen?
all x values would stay the same and y would go its opposite
A(1,4) ---> A'(1, -4)
B(3,-2) ----> ......
C(4,2) -----> .....
To find the coordinates of the image A', B', and C' after a reflection over the x-axis, we need to change the sign of the y-coordinate of each point.
Given the coordinates of the original triangle ABC:
A(1, 4)
B(3, -2)
C(4, 2)
To reflect over the x-axis, we need to change the sign of the y-coordinate. The x-coordinate remains the same.
Coordinates of A' = (1, -4)
Coordinates of B' = (3, 2)
Coordinates of C' = (4, -2)
So, the coordinates of the image A', B', and C' after the reflection over the x-axis are:
A'(1, -4)
B'(3, 2)
C'(4, -2)