60% of all bald eagles survive their first year of life. Give your answers as decimals, not percents. If 43 bald eagles are randomly selected, find the probability that

a. Exactly 26 of them survive their first year of life.

b. At most 25 of them survive their first year of life.

c. At least 24 of them survive their first year of life.

d. Between 21 and 25 (including 21 and 25) of them survive their first year of life.

e. Find the mean:  μ=


e. Find the standard deviation:  σ=

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To solve these probabilities, we need to use the binomial probability formula. The general formula for the probability of getting exactly k successes in n trials, where the probability of success in each trial is p, is:

P(X=k) = C(n,k) * p^k * (1-p)^(n-k)

where C(n,k) is the number of combinations of n items taken k at a time.

For this problem, we have the following given information:

p = 0.6 (the probability of survival for each bald eagle)
n = 43 (the number of bald eagles selected)

Let's solve the probabilities step by step:

a. Exactly 26 of them survive their first year of life.
P(X=26) = C(43,26) * 0.6^26 * (1-0.6)^(43-26)
P(X=26) = 0.1150 (rounded to 4 decimal places)

b. At most 25 of them survive their first year of life.
We need to sum the probabilities from 0 to 25, because we want to find the probability of having 25 or fewer successes.
P(X≤25) = P(X=0) + P(X=1) + P(X=2) + ... + P(X=25)

Using a probability calculator, we find that P(X≤25) ≈ 0.0060 (rounded to 4 decimal places).

c. At least 24 of them survive their first year of life.
We need to sum the probabilities from 24 to 43, because we want to find the probability of having 24 or more successes.
P(X≥24) = P(X=24) + P(X=25) + P(X=26) + ... + P(X=43)

Using a probability calculator, we find that P(X≥24) ≈ 0.3797 (rounded to 4 decimal places).

d. Between 21 and 25 (including 21 and 25) of them survive their first year of life.
We need to sum the probabilities from 21 to 25, because we want to find the probability of having 21, 22, 23, 24, or 25 successes.
P(21≤X≤25) = P(X=21) + P(X=22) + P(X=23) + P(X=24) + P(X=25)

Using a probability calculator, we find that P(21≤X≤25) ≈ 0.3634 (rounded to 4 decimal places).

e. Mean (μ):
The mean of a binomial distribution is given by μ = n * p.
μ = 43 * 0.6
μ = 25.8

So, the mean is approximately 25.8.

f. Standard Deviation (σ):
The standard deviation of a binomial distribution is given by σ = sqrt(n * p * (1-p)).
σ = sqrt(43 * 0.6 * 0.4)
σ = sqrt(10.32)
σ ≈ 3.21

So, the standard deviation is approximately 3.21.

To find the probability for each question, we will use the binomial distribution formula:

P(X = k) = (n C k) * p^k * q^(n-k)

where:
- n is the number of trials or observations (43 in this case)
- k is the number of successful outcomes (the number of bald eagles surviving their first year of life)
- (n C k) represents the number of combinations of n things taken k at a time
- p is the probability of success (60% or 0.6 in decimal form)
- q is the probability of failure (100% - p or 0.4 in decimal form)

a. To find the probability that exactly 26 bald eagles survive their first year of life:
P(X = 26) = (43 C 26) * (0.6^26) * (0.4^(43-26))
= (43! / (26! * (43-26)!)) * (0.6^26) * (0.4^17)
You can calculate this using a calculator or statistical software to get the final decimal value.

b. To find the probability that at most 25 bald eagles survive their first year of life:
P(X ≤ 25) = P(X = 0) + P(X = 1) + ... + P(X = 25)
Calculate the probability for each individual value of k and sum them up.

c. To find the probability that at least 24 bald eagles survive their first year of life:
P(X ≥ 24) = 1 - P(X < 24)
Calculate the probability for each individual value of k less than 24 and subtract them from 1.

d. To find the probability that between 21 and 25 bald eagles survive their first year of life:
P(21 ≤ X ≤ 25) = P(X = 21) + P(X = 22) + ... + P(X = 25)
Calculate the probability for each individual value of k within the range and sum them up.

To find the mean (μ) and standard deviation (σ), we will use the formulas:
μ = n * p
σ = sqrt(n * p * q)

Substitute the values (n, p, and q) into the formulas to find the values for μ and σ.

Please note that the calculations may involve large factorials, so using a calculator or statistical software is recommended.