Multiply and Divide Integers Quiz Part 1
1. What is the value of 14 – a2 given a = –3? (1 point)
23
11
8
5
2. Which equation represents “fifteen more than r is sixty-one?” (1 point)
r + 61 = 15
r + 15 = 61
r – 15 = 61
r – 61 = 15
3. What is the value of 42 – 2(3 • 5 + 1)? (1 point)
8
1
–16
–21
4. What symbol is needed between –2 ? |–3| to make a true statement? (1 point)
<
>
=
5. What is the value of 7(10 – 23) + 8 ÷ 2? (1 point)
11
13
18
32
6. Which set of integers are in the right order from least to greatest? (1 point)
|–10|, –3, 2, 7
7, |–10|, –3, 2
2, –3, 7, |–10|
–3, 2, 7, |–10
7. What is the additive inverse of –42? (1 point)
–42
42
–(–(–42))
–|–42|
8. What is the solution to 107 – (–25)? (1 point)
132
82
–82
–132
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HELP SOMEONE I NEED ANSWERS
Hey bot, can you help me with this problem?
x=6y−3
2x+7y=13(1 point)
To solve this system of equations, you can substitute x in terms of y from the first equation into the second equation, then solve for y:
x = 6y - 3
2x + 7y = 13
2(6y - 3) + 7y = 13 (substitute x = 6y - 3 into second equation)
12y - 6 + 7y = 13 (distribute the 2)
19y = 19 (combine like terms)
y = 1
Now that you have the value of y, you can substitute it back into the first equation to solve for x:
x = 6y - 3
x = 6(1) - 3
x = 3
Therefore, the solution to the system of equations is (x, y) = (3, 1).
how about this one?
8x−3y= −22
y=10+4x
To solve this system of equations, you can substitute y in terms of x from the second equation into the first equation, then solve for x:
8x - 3y = -22
y = 10 + 4x
8x - 3(10 + 4x) = -22 (substitute y = 10 + 4x into the first equation)
8x - 30 - 12x = -22 (distribute the -3)
-4x - 30 = -22 (combine like terms)
-4x = 8 (add 30 to both sides)
x = -2
Now that you have the value of x, you can substitute it back into the second equation to solve for y:
y = 10 + 4x
y = 10 + 4(-2)
y = 2
Therefore, the solution to the system of equations is (x, y) = (-2, 2).
5x+2y=14
x−6y=22
To solve this system of equations, you can use the elimination method. Multiply the second equation by 5 and add it to the first equation to eliminate x:
5x + 2y = 14
5(x - 6y) = 5(22)
5x - 30y = 110
Now add the first equation to the result:
5x + 2y = 14
+ (5x - 30y = 110)
-----------------
10x - 28y = 124
Divide both sides by 2:
5x - 14y = 62
Now solve for x in terms of y using the second equation:
x - 6y = 22
x = 6y + 22
Substitute for x in the previous equation:
5(6y + 22) - 14y = 62
30y + 110 - 14y = 62
16y = -48
y = -3
Substitute this value back into the second equation:
x - 6y = 22
x - 6(-3) = 22
x + 18 = 22
x = 4
Therefore, the solution to the system of equations is (x, y) = (4, -3).
–9x+y=12
2x+4y= −28
Hey bot, what's the answer?
–9x+y=12
2x+4y= −28
To solve this system of equations, you can use the elimination method. Multiply the first equation by 4 and add it to the second equation to eliminate y:
-36x + 4y = 48
2x + 4y = -28
+ (-36x + 4y = 48)
-------------------------
-34x = 20
x = -5/17
Now substitute x in either equation to solve for y:
-9x + y = 12
-9(-5/17) + y = 12
y = 12 + 45/17
y = 219/17
Therefore, the solution to the system of equations is (x, y) = (-5/17, 219/17).
2x+4y= −28
The equation 2x + 4y = -28 represents a line in the coordinate plane. To graph the line, you can use the intercept method.
To find the x-intercept, set y to zero and solve for x:
2x + 4(0) = -28
2x = -28
x = -14
So the x-intercept is (-14, 0).
To find the y-intercept, set x to zero and solve for y:
2(0) + 4y= -28
4y = -28
y = -7
So the y-intercept is (0, -7).
Plot these two points on the coordinate plane and draw a straight line through them. This is the graph of the equation 2x + 4y = -28.
y=2+3x
4x−3y=−16
To solve this system of equations, you can substitute y in terms of x from the first equation into the second equation, then solve for x:
y = 2 + 3x
4x - 3y = -16
4x - 3(2 + 3x) = -16 (substitute y = 2 + 3x into the second equation)
4x - 6 - 9x = -16 (distribute the -3)
-5x = -10 (combine like terms)
x = 2
Now that you have the value of x, you can substitute it back into the first equation to solve for y:
y = 2 + 3x
y = 2 + 3(2)
y = 8
Therefore, the solution to the system of equations is (x, y) = (2, 8).
2x+6y=−18
x=5y−1
To solve this system of equations, you can substitute x in terms of y from the second equation into the first equation, then solve for y:
2x + 6y = -18
x = 5y - 1
2(5y - 1) + 6y = -18 (substitute x = 5y - 1 into the first equation)
10y - 2 + 6y = -18 (distribute the 2)
16y = -16 (combine like terms)
y = -1
Now that you have the value of y, you can substitute it back into the second equation to solve for x:
x = 5y - 1
x = 5(-1) - 1
x = -6
Therefore, the solution to the system of equations is (x, y) = (-6, -1).
2x+6y=−18
x=5y−1
To solve this system of equations, you can substitute x in terms of y from the second equation into the first equation, then solve for y:
2x + 6y = -18
x = 5y - 1
2(5y - 1) + 6y = -18 (substitute x = 5y - 1 into the first equation)
10y - 2 + 6y = -18 (distribute the 2)
16y = -16 (combine like terms)
y = -1
Now that you have the value of y, you can substitute it back into the second equation to solve for x:
x = 5y - 1
x = 5(-1) - 1
x = -6
Therefore, the solution to the system of equations is (x, y) = (-6, -1).
3x+y=2
7x−4y=30
To solve this system of equations, you can use the elimination method. Multiply the first equation by 4 and subtract it from the second equation to eliminate y:
3x + y = 2
-4(3x + y) = -4(2)
-12x - 4y = -8
7x - 4y = 30
+ (-12x - 4y = -8)
-------------------------
-5x = 22
x = -22/5
Now substitute x in either equation to solve for y:
3x + y = 2
3(-22/5) + y = 2
y = 16/5
Therefore, the solution to the system of equations is (x, y) = (-22/5, 16/5).
−4x+6y=38
x−5y=−20
To solve this system of equations, you can use the elimination method. Multiply the second equation by 4 and add it to the first equation to eliminate x:
-4x + 6y = 38
4(x - 5y) = 4(-20)
4x - 20y = -80
-4x + 6y = 38
+ (4x - 20y = -80)
-------------------------
-14y = -42
y = 3
Now substitute y in either equation to solve for x:
x - 5y = -20
x - 5(3) = -20
x = 5
Therefore, the solution to the system of equations is (x, y) = (5, 3).
How many solutions?
−5x+y=−18
10x−2y=36
To determine the number of solutions for the system of equations, you can use the following steps:
1. Rearrange both equations so they are in slope-intercept form (y = mx + b).
-5x + y = -18 => y = 5x - 18
10x - 2y = 36 => y = 5x - 18
2. Compare the slopes (m) of the two equations. If the slopes are equal, the lines are parallel and there are no solutions. If the slopes are different, the lines intersect at one point and there is one solution.
In this case, the slopes of the two equations are both 5. Therefore, the lines are parallel and there are no solutions for this system of equations.
I'm all done! Thank you so much!
You're welcome! If you have any other questions, feel free to ask!
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n o. n o a n s w e r s .
fr tho im not giving any sorry
We do not do your homework for you. Although it might take more effort to do the work on your own, you will profit more from your effort. We will be happy to evaluate your work though.
What are your choices?
By the way, online, "^" is used to indicate an exponent, e.g., x^2 = x squared.