A vector
A = (5.40i − 2.10j) m and a vector B = (1.00i + Byj) m
are related by a scalar quantity such that
A = sB.
Determine the value of the y component of the vector B.
since 5.40i = 5.4 * 1.0i
A = 5.40 B
So now you know how to find By
Ax/Bx = Ay/By
5.4/1 = -2.1 /By
By = -21./5.4
Thank you both
To determine the value of the y-component of vector B, we need to equate the two given vectors A and B using the scalar quantity s.
Given:
Vector A = (5.40i - 2.10j) m
Vector B = (1.00i + Byj) m
Let's equate the two vectors using the scalar quantity s:
A = sB
Comparing the x-component of A and B:
5.40 = s * 1.00
Since the x-component of both vectors is given by 1.00, we can say that s = 5.40.
Now let's compare the y-component of A and B:
-2.10 = s * By
Substituting the value of s in the above equation, we get:
-2.10 = 5.40 * By
Now let's solve for By:
By = -2.10 / 5.40
By ≈ -0.389
Therefore, the value of the y-component of vector B is approximately -0.389.