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algebra

Write the equation of the line that goes through the point (6, 5) and is perpendicular to the line y = 3x + 8.
What is the slope of y = 3x + 8? __
m = __
Since your line is perpendicular to y = 3x + 8, your slope has the opposite sign and reciprocal (flip the fraction) slope. "M" your line = __
Use your slope and given point to solve for "b" and write the equation.

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  1. the slope of y = 3x + 8 is 3
    so the slope of the perpendicular line is -1/3

    new line must be y = (-1/3)x + b , with (6,5) lying on it, so
    5 = (-1/3)(6) + b
    5 = -2 + b
    b = 7

    looks like y = (-1/3)x + 7

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  2. Thanks for your help mathhelper

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