# PreCalculus

An astronaut on the moon throws a baseball upward. The astronaut is 6​ ft, 6 in.​ tall, and the initial velocity of the ball is 50 ft per sec. The height s of the ball in feet is given by the equation ​s=-2.7t^2+50t+6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b.

A.) After how many seconds is the ball 10ft above the moon's surface?
B.) how many seconds will it take for the ball to hit the moon's surface?

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1. a)
10 = -2.7t^2 + 50t + 6.5
2.7t^2 - 50t + 3.5 = 0

solve for t , using the quadratic formula, remember you have 2
both are valid, one is on the way up, the other on the way down

b) solve
-2.7t^2 + 50t + 6.5 = 0 , again using the quadratic formula

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