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the first 3 term of a geometric progression are k4, 2k4, 4k+4. what is the value of k? can someone help please! in any geometric progression any term divided by its previous term gives you the common ratio, so .... (2k4)/(k4)
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how do i find the pattern for: 4,8,12,16 if the last number is negative, multiply by 1 then add 4 if the last number is positive, add 4, then multiply by 1 or how about termn+1 = (abs(termn))*(1)^n, where term1 = 4, n>0 oops
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The problem to solve is: (x+20)(x12)(x+4)>0 but I can't figure out how to do this right so I left off the >0 and tried to solve the equation. x+20 evaluates to x+20 x12 evaluates to x12 Multiplying x+20 by x12 is a classic
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HI STEVE, THANKS for your reply back it was the wrong answer the one you worked, yes a hard question, here is an example of simultaneous questions. x2/3 + y1/4 =13/12 (1) 2x/2 + 3+y/3 =11/6 (2) first step is to get rid of
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