Find the final amount of money in an account if $3,300 is deposited at

6% interest compounded quarterly (every 3 months) and the money is left for 8 years.
The final amount is $
Round answer to 2 decimal places

Answer plsss!

Well, let's do some math! If $3,300 is deposited at 6% interest compounded quarterly for 8 years, then the formula to find the final amount is:

A = P * (1 + r/n)^(n*t)

Where:
A = Final amount
P = Principal amount ($3,300)
r = Annual interest rate (6% or 0.06)
n = Number of times interest is compounded per year (quarterly, so 4 times)
t = Number of years (8)

Plugging in these values, we get:

A = 3300 * (1 + 0.06/4)^(4*8)

Calculating this expression, the final amount comes out to be $6,094.25. So, the final amount in the account after 8 years would be $6,094.25.

Hope that helps!

To find the final amount of money in the account, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:
A = Final amount
P = Principal amount (initial deposit)
r = Annual interest rate (in decimal form)
n = Number of times interest is compounded per year
t = Number of years

In this case, the principal amount (P) is $3,300, the annual interest rate (r) is 6% (or 0.06), the interest is compounded quarterly (n = 4 times per year), and the money is left in the account for 8 years (t = 8).

Plugging these values into the formula:

A = 3300(1 + 0.06/4)^(4 * 8)

Calculating the exponent:

A = 3300(1 + 0.015)^32

A = 3300(1.015)^32

Calculating (1.015)^32:

A = 3300(1.5262917)

A ≈ $5,036.98

Therefore, the final amount in the account after 8 years will be approximately $5,036.98 (rounded to 2 decimal places).

To find the final amount of money in an account with compound interest, we can use the formula:

A = P * (1 + r/n)^(nt)

where:
A = the final amount of money
P = the principal amount (initial deposit)
r = annual interest rate (in decimal form)
n = number of times interest is compounded per year
t = time in years

In this case, the given information is:
P = $3,300
r = 6% = 0.06 (in decimal form)
n = 4 (compounded quarterly)
t = 8 years

Let's substitute the values into the formula and solve for A:

A = 3300 * (1 + 0.06/4)^(4*8)

Now, let's simplify and calculate the exponent first:

A = 3300 * (1 + 0.015)^(32)
A = 3300 * (1.015)^(32)

Now, let's raise 1.015 to the power of 32:

A = 3300 * 1.52071076074458

Finally, multiply the principal amount by the calculated value:

A ≈ $5,016.54

So, the final amount of money in the account, rounded to 2 decimal places, is approximately $5,016.54.

A = 3300 [1 + (.06 / 4)]^(8 * 4)