A diver is 40 meters deep under the water where the temperature is 4◦C. From the diver’s
gas mask an air bubble is released with volume 20 cm3
. The bubble rises to the surface where the
temperature is 20◦C. What will the volume of the bubble be at the surface
say pressure at surface = 10^5 Pascals (Newtons/m^2)
pressure at 40 m =10^5 + rho g H = 10^5+1000 kg/m^3 * 9.81m/s^2 *40m
= 10^5 + 3.92*10^5 = 4.92*10^5
Ts = 273+20 = 293 K
Td = 273+4 = 277 K
P V / T = nR = 4.92 *20 / 277 = 1 * V / 293