An inlet tap can fill an empty tank in 6 hours .it takes 10 hours to fill the tank when inlet tap and outlet tap are both opened at same time .calculate the time the outlets tap takes to empty the full tank when inlet tap is closed
I need all the calculations
I want all the calculations of that sum
To calculate the time the outlet tap takes to empty the full tank when the inlet tap is closed, we need to find out the rate at which the outlet tap can empty the tank.
Let's assume that the tank has a capacity of 1 unit (you can consider any suitable unit of measurement).
In the first scenario, where only the inlet tap is open, it takes 6 hours to fill the tank. Therefore, the inlet tap can fill 1/6 of the tank in 1 hour.
In the second scenario, where both the inlet tap and outlet tap are open, it takes 10 hours to fill the tank. This means that in one hour, the combined rate of both taps is 1/10 of the tank's capacity. Since the inlet tap alone can fill 1/6 of the tank in one hour, the rate at which the outlet tap empties the tank is (1/6 - 1/10) of the tank's capacity in one hour.
To simplify the calculation, we can find a common denominator for 6 and 10, which is 30.
(1/6 - 1/10) = (5/30 - 3/30) = 2/30 = 1/15
So, when the inlet tap is closed, the outlet tap can empty 1/15 of the tank's capacity in one hour.
Therefore, it would take the outlet tap 15 hours to empty the full tank when the inlet tap is closed.
1/6 - 1/x = 1/10
find x