When 3.00 mol of NH3(g) were placed into an evacuated 15.0 dm3 container at 963 K and the reaction reached equilibrium the pressure in the container was found to be 2.4×10^6 Pa. The volume of the container was then changed and reaction alloed to reach equilibrium for the second time. At the second equilibrium the moles of H2(g) was found to be 45.9% less than it was at the first equilibrium. Culculate the new volume of the container?
