A bullet of mass 13 g strikes a ballistic pendulum of mass 1.7 kg. The center of mass of the pendulum rises a vertical distance of 11 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet’s initial speed. Round your answer off to one place after the decimal.
the PE at the top of the swing is mgh = (1.7+0.013)*9.81*0.11 = 1.848J
so, that must have been equal to the bullet's KE: 1/2 mv^2 = 1.848