A force of 18N stretches a spring a total length of 30N .an additional force of 10N strctches the spring 5cm further .find the natural length of the spring
If the natural length is L, then
(30-L)/(18-0) = (30+10-L)/(18+5)
(30-L)/(18-0) = (30+10-L)/(18+5)