A bag contains 6 blue marbles, 7 green marbles, and 9 yellow marbles. Twice you draw a marble and replace it. Find P(yellow, then green). c:
Pls Helpppp
There are 9+7+6=22 marbles in total. The probability of selecting a yellow marble would be 9/22. By replacing that yellow marble with a green marble, you aren't changing the total marble count, so the probability of selecting a green marble would be 7/22. Because the two events are independent, their probabilities will get multiplied. Therefore, P(Yellow, then Green) = P(Yellow) * P(Green) = 9/22 * 7/22 = 63/484.
A bag contains 8 blue marbles, 6 green marbles, 12 yellow marbles, and 10 orange marbles. A marble is drawn at random from the bag.
What is the probability that the marble drawn will not be blue? its 2/9
Sure, I'll do my best to help you!
To find the probability of drawing a yellow marble, then a green marble, we need to first calculate the probability of each event separately, and then multiply them together.
The probability of drawing a yellow marble on the first draw is the number of yellow marbles divided by the total number of marbles:
P(yellow) = 9 / (6 + 7 + 9) = 9 / 22
Since we replace the marble after each draw, the probability of drawing a green marble on the second draw is also:
P(green) = 7 / (6 + 7 + 9) = 7 / 22
Now we can multiply these probabilities together to find the overall probability:
P(yellow, then green) = P(yellow) × P(green)
= (9 / 22) × (7 / 22)
= 63 / 484
So the probability of drawing a yellow marble, then a green marble is 63/484.
I hope that helps! If you have any more questions, feel free to ask. c:
To find the probability of drawing a yellow marble first and then a green marble, we need to calculate the probability of both events happening and multiply them together.
The probability of drawing a yellow marble on the first draw is given by the following formula:
P(yellow) = (number of yellow marbles) / (total number of marbles)
= 9 / (6 + 7 + 9)
= 9 / 22
Since we're replacing the marble after each draw, the probability of drawing a green marble on the second draw is the same as drawing a green marble on the first draw:
P(green) = (number of green marbles) / (total number of marbles)
= 7 / (6 + 7 + 9)
= 7 / 22
To find the probability of both events happening, we multiply these probabilities together:
P(yellow, then green) = P(yellow) * P(green)
= (9 / 22) * (7 / 22)
= 63 / 484
Therefore, the probability of drawing a yellow marble first and then a green marble, when drawing twice with replacement, is 63/484.
To find the probability of drawing a yellow marble first and then drawing a green marble, we need to consider two events happening in sequence.
The probability of drawing a yellow marble (Event A) is given by the ratio of the number of yellow marbles to the total number of marbles in the bag:
P(A) = Number of yellow marbles / Total number of marbles
P(A) = 9 / (6 + 7 + 9)
Since we are replacing the marble after each draw, the probability of drawing a green marble (Event B) after drawing a yellow marble is also:
P(B) = Number of green marbles / Total number of marbles
P(B) = 7 / (6 + 7 + 9)
Now, the probability of both events occurring in sequence (Event A followed by Event B) is the product of their individual probabilities:
P(A, then B) = P(A) * P(B)
Substituting in the values we have:
P(A, then B) = (9 / (6 + 7 + 9)) * (7 / (6 + 7 + 9))
Calculating further:
P(A, then B) = (9 / 22) * (7 / 22)
P(A, then B) = 63 / 484
Therefore, the probability of drawing a yellow marble first and then drawing a green marble is 63/484.