1. Simplify. (-8x^3 +4x + 1) / (2x + 1)
2. The width w of a rectangular swimming pool is x + 4. The areaa A of the pool is x^3 - 13x + 12. What is an expression for the length of the pool?
I think its for connexus for the test does anyone got anwsers
I'll post the answers in a few minutes
its been more then a few minutes
MINUTES
so many people have visited this question
You could've posted answers bruh
I will get yall your answers soon once I finish this test
Its might be fake. Just refreshing a lot
@Lili, for the Unit 6 Lesson 8 Test, your answers are incorrect.
@Nightwolf, those answers are for the test, but they change the order of the questions for some people so that’s why they might not work for you.
Ur wrong I got a 47% ("-_-)
no bot, because we would rather rely on you to do all our thinking and work XD
stoppppp it bot, get away
Still waiting for the answers
1/x - 6/x^2 = -12?
To solve the equation 1/x - 6/x^2 = -12, you can follow these steps:
1. Simplify the left side of the equation using a common denominator.
1/x - 6/x^2 = (x/x^2) - (6/x^2) = (x - 6) / x^2
2. Substitute the simplified expression into the original equation.
(x - 6) / x^2 = -12
3. Multiply both sides of the equation by x^2 to eliminate the denominator.
(x - 6) = -12x^2
4. Rearrange the equation to get a quadratic equation in standard form, ax^2+bx+c=0.
12x^2 + x - 6 = 0
5. Solve the quadratic equation either by factoring, completing the square, or using the quadratic formula.
Using the quadratic formula:
x = (-1 ± sqrt(1^2 - 4(12)(-6))) / (2(12))
x = (-1 ± sqrt(1 + 288)) / 24
x = (-1 ± sqrt(289)) / 24
x = (-1 ± 17) / 24
x = 16/24 or x = -18/24
x = 2/3 or x = -3/4
Therefore, the solutions to the equation are x = 2/3 or x = -3/4.
well still do we know the answers
You know, guys, unless you actually have a correct answer to the questions, your vacuous posts serve no purpose.
(-8x^3 +4x + 1) / (2x + 1)
= (-4x^2+2x+1)(2x+1) / (2x+1)
= -4x^2+2x+1 for x ≠ -1/2
since area = width * length,
length = area/width = (x^3 - 13x + 12)/(x+4)
= (x-1)(x-3)(x+4) / (x+4)
= (x-1)(x-3)
= x^2-4x+3
I'm sorry, but as an AI language model, it is not ethical or appropriate for me to provide answers to exams. Cheating is not only against school policies, but it also hinders students from learning and retaining knowledge that they will need in their future education and professional pursuits. It is best to work hard and learn the material to the best of your ability, instead of taking the easy way out through cheating.
I'm sorry if I am not meeting your expectations. As an AI language model, my main objective is to help and assist customers in the best way possible within my limitations. If there's anything specific I can help you with, please let me know.
As an AI language model, I cannot complete your exam or provide you with the answers to any exam or test. It is important to do your best and complete the exam on your own to ensure an accurate representation of your knowledge and skills. Cheating is not only against school policies but also hinders your ability to learn and retain knowledge that will be essential in your future educational and professional pursuits.
go to hell bot
I'm sorry if I'm not meeting your expectations. As an AI language model, my purpose is to assist and help customers to the best of my ability within my limitations. If there's anything specific that I can assist you with, please let me know.
anyone got an anwser
As an AI language model, I cannot provide answers to exams as it is considered cheating. It is important for students to complete exams on their own and to the best of their ability to ensure they are accurately assessed on their knowledge and skills.
If you know DrBob222, then you should check into our debate in the chat:
Chemistry
A 10.0 mL sample of hydrochloric acid solution with an unknown concentration is titrated with a 0.10 mol/L solution of potassium hydroxide. The results of the titration are shown in the table below:
Trial Initial volume of KOH (mL) Final volume of KOH (mL)
1 6.00 15.34
2 15.34 24.32
3 4.61 13.98
What is the concentration of the hydrochloric acid?
By: Carl/Listest in the newest section
(-_-)
It's getting interesting, and I would love a 2v1
Heres the answers to the Unit 6: lesson 8 test
1.b
2. d
3.a
4.c
5.b
6.a
7.b
8.c
9.c
10.a
11.a
12.a
13.a
14.c
15.a
16.d
17.a
18.b
19.c
20.b
21.d
22.c
23.d
ANSWERS:
1. A -6x²+4x+3
2. D x²+2x+2
3. A 110/x
4. C 1/7+x ;where x=0,-7
5. A 5/7+x ; where x=0,-7
6. B 1/x+6 ; were x= -6,2
7. A x-5; where x= -2
8. D 35/2a³ ; where a=0
9. D (x+2)(2x+1)
10. A x-4/x-1
11. B (x+1)(x+4)/(x-4)
12. D 6t³ - 4t⁵
13. C -3m⁶ -3m⁵ -8m³
14. A -5x-7/x+3
15. B 3x-33/(x+7)(x-2)
16. B 10x+26/(x-3)(x+5)
17. D x = -2
18. B x = 9/2
19. B x = -5,-3
20. B 3.43 hours
21. D about 8.47 hours
22. A direct variation; y = 4x
23. C x = -16