which of the following changes will increase the frequency of an oscillating pendulum?
a. an increase in the mass of the pendulum.
b. an increase in the initial height of release.
c. an increase in the length of the rope.
d. more than one of the above
e. none of the above
explain your answer
I chose c. How do I explain my answer.
it will be hard, since it is wrong.
do some reading on pendulums and their periods
does not depend on mass
does not depend much on initial release height, but second order higher would be lower, not higher frequency
frequency goes DOWN (period up) with longer rope
so in the end e
So it's e because a pendulum can increase frequency if it had a stronger gravity field or by shortening the rope of the pendulum itself.
To explain why an increase in the length of the rope, option c, would increase the frequency of an oscillating pendulum, you can refer to the formula for the period of a pendulum.
The period of a pendulum is given by the equation T = 2π√(L/g), where T is the period, L is the length of the rope, and g is the acceleration due to gravity. The frequency of the pendulum, f, is the reciprocal of the period, so f = 1/T.
When you increase the length of the rope, L, in the formula, the period, T, of the pendulum also increases. Since frequency is the reciprocal of the period, an increase in the period results in a decrease in the frequency. Therefore, option c is incorrect.
So, in this case, the correct answer would be option e, "none of the above," because increasing the length of the rope actually decreases the frequency of an oscillating pendulum.
If you had to explain your answer, you would clarify that the correct choice to increase the frequency of an oscillating pendulum is not mentioned among the given options.