I am a multiple of 7. my ones digit is half of the tens digit. If you double it , you get a number between 40 and 50. When you add it to an odd number , you get an even number.
u want the answer
odd+odd = even, so the number after doubling must be odd.
Since doubling produced a number in the 40's, the original number must be in the 20's.
Looks like 21 to me
18
To find the number that satisfies all the given conditions, we can use a step-by-step approach:
Step 1: Find the possible values for the tens digit.
Since the ones digit is half of the tens digit, the possible values for the tens digit are 2, 4, 6, or 8.
Step 2: Find the possible values for the ones digit.
If the tens digit is 2, the ones digit could be 1 (2 divided by 2).
If the tens digit is 4, the ones digit could be 2 (4 divided by 2).
If the tens digit is 6, the ones digit could be 3 (6 divided by 2).
If the tens digit is 8, the ones digit could be 4 (8 divided by 2).
Step 3: Find the number that satisfies all the given conditions.
Using the possible values for the tens and ones digit, we get 21, 42, 63, or 84 as potential numbers.
Step 4: Check whether doubling the ones digit gives a number between 40 and 50.
If we double 1, we get 2 (not between 40 and 50).
If we double 2, we get 4 (not between 40 and 50).
If we double 3, we get 6 (not between 40 and 50).
If we double 4, we get 8 (not between 40 and 50).
Since none of the potential numbers meet this condition, we conclude that there is no number that satisfies all the given conditions.