Kai flips a coin and spins a spinner with three equal parts labeled one, two and three. Predict the number of times Kai will get the outcome (heads, 2) in 300 trials.
There are 2*3=6 possible outcomes.
Only 1 is a success, so 1/6 * 300 = 50
The spinner doesn't care what the coin does, nor is it affected by it, so
prob(your event) = (1/2)(1/3) = ...
So if we do this 300 times we would expect what number ?
To predict the number of times Kai will get the outcome (heads, 2) in 300 trials, we can use the concept of probability.
1. The probability of getting heads on a coin flip is 1/2, assuming it is a fair coin.
2. The probability of getting a 2 on the spinner is 1/3, assuming it is fair and equally divided.
Now, we can calculate the probability of getting both (heads, 2) in a single trial:
Probability of getting heads and 2 = Probability of getting heads × Probability of getting 2
= (1/2) × (1/3)
= 1/6
This means that in a single trial, the probability of getting both (heads, 2) is 1/6.
To predict the number of times this outcome will occur in 300 trials, we can multiply the probability of a single trial outcome by the number of trials:
Number of times (heads, 2) in 300 trials = Probability of (heads, 2) × Number of trials
= (1/6) × 300
= 50
Therefore, based on these calculations, we can predict that Kai will get the outcome (heads, 2) approximately 50 times in 300 trials.
To predict the number of times Kai will get the outcome (heads, 2) in 300 trials, we need to consider the probability of each event happening and multiply them together.
First, let's calculate the probability of getting heads on a coin flip. Since there are two possible outcomes (heads or tails) and they are equally likely, the probability of getting heads is 1/2.
Next, let's calculate the probability of getting a 2 on the spinner. Since there are three equally likely outcomes (1, 2, or 3) and only one of them is the desired outcome, the probability of getting a 2 is 1/3.
To find the probability of both events happening (getting heads and 2), we multiply the probabilities together: (1/2) * (1/3) = 1/6.
Now, to predict the number of times Kai will get the outcome (heads, 2) in 300 trials, we multiply the probability by the number of trials: (1/6) * 300 = 50.
Therefore, we can predict that Kai will get the outcome (heads, 2) approximately 50 times in 300 trials.