use Boyle's law to solve for the missing value in each of the following: v1=2.4 x10^5l, p2 = 180mm hg, v21.8 x 13^3 l, p1=?
1.35
To use Boyle's law to solve for the missing value, we can set up the equation as:
P1 x V1 = P2 x V2
where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
Given:
V1 = 2.4 x 10^5 L
P2 = 180 mmHg
V2 = 21.8 x 13^3 L
Let's substitute the known values into the equation:
P1 x (2.4 x 10^5 L) = (180 mmHg) x (21.8 x 13^3 L)
Now, we need to convert the pressure from mmHg to the same units as P1 (L). Since we know that 1 atm = 760 mmHg, we can set up the conversion factor:
180 mmHg x (1 atm / 760 mmHg) = 0.23684 atm
Now, let's substitute the values into the equation:
P1 x (2.4 x 10^5 L) = (0.23684 atm) x (21.8 x 13^3 L)
Now, we can solve for P1 by canceling out the common volume term:
P1 = (0.23684 atm) x (21.8 x 13^3 L) / (2.4 x 10^5 L)
P1 = 0.23684 atm x 21.8 x 13^3 L / 2.4 x 10^5 L
P1 ≈ 0.23684 atm x 21.8 ≈ 5.157 atm
Therefore, the approximate value of P1 is 5.157 atm.
To solve for the missing value using Boyle's Law, we can use the equation:
P1 x V1 = P2 x V2
Given:
V1 = 2.4 x 10^5 L
P2 = 180 mmHg
V2 = 1.8 x 13^3 L
We need to find P1.
1. Convert the given units to a consistent unit. In this case, let's convert mmHg to L, so we have:
1 mmHg = 1.33 x 10^-3 L
Therefore, P2 = 180 x 1.33 x 10^-3 L = 0.24 L
2. Substitute the values into Boyle's Law equation:
P1 x V1 = P2 x V2
P1 x 2.4 x 10^5 L = 0.24 L x 1.8 x 13^3 L
3. Simplify the equation:
P1 = (0.24 L x 1.8 x 13^3 L) / (2.4 x 10^5 L)
P1 = 3.06 x 10^-3
Therefore, the missing value, P1, is approximately 3.06 x 10^-3.
well, p1*v1 = p2*v2
so plug in your numbers.