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A race car starts from rest on a circular track of radius 400 m. Its speed increases at the constant rate of 0.500 m/s2. At the point where the magnitudes of the radial acceleration is twice the tangential acceleration, determine (a) the speed of the race car, and (b) the elapsed time.

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YOYO

  1. hey wants the answer?

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    hey i um

  2. tangential a = 0.5 m/s^2
    so
    v = 0.5 t

    radial a = v^2/R = 0.25 t^2/ 400 = 0.000625 t^2
    at radial acc = 1.0 m/s^2 which is twice a
    1.0 = 0.000625 t^2
    t^2 = 1600
    t = 40 seconds
    v = 0.5 t = 20 m/s

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    Anonymous

  4. big hurry?

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    Anonymous

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