The area of an isosceles trapezoid is 36 square units. Its hight is 4 units. What is the sum of its bases?
Please, thank you.
A = (B+b)/2 * h
(B+b) = 2A/h
so plug in your numbers
To find the sum of the bases of an isosceles trapezoid, we need to use the formula for the area of a trapezoid. The formula is:
Area = (1/2) * (sum of bases) * height
Given that the area is 36 square units and the height is 4 units, we can rearrange the formula to solve for the sum of the bases:
(1/2) * (sum of bases) * 4 = 36
Multiply both sides of the equation by 2:
(sum of bases) * 4 = 72
Divide both sides of the equation by 4:
sum of bases = 72 / 4
sum of bases = 18
Therefore, the sum of the bases of the isosceles trapezoid is 18 units.