Physics



When an object of mass m1 is hung on a vertical spring and set into vertical simple harmonic motion, its frequency is 12 Hz. When another object of mass m2 is hung on the spring along with m1, the frequency of the motion is 4 Hz. Find the ratio m2/m1 of the masses.



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Physics HELP!!!!!!!! - bobpursley, Wednesday, April 4, 2007 at 9:12pm
w= sqrt (k/m)

w^2= k/m

(w1/w2)^2=9 = (m1+m2)/m1

9= 1 + m2/m1

check my thinking.


Now, Bob why did u equate 9 to (m1 + m2)/m1?


cos one mass wass added to the other. Man, I wish i could break down questions like you do


The ratio of the hanging masses (m1+m2)/m1 is inversely proprtional to square of the ratio of the frequencies (which is 9 in this case). That follows from the equation
w= sqrt (k/m), and the fact that k is constant.

asked by Papito
  1. An object in static equilibrium has a coefficient of static friction as 0.110. If the normal force acting on the object is 95.0 newtons, what is the mass of the object?

    posted by ksg
  2. the ans is

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