Find the 8th term of the arithmetic sequence if a1=4, d=5
To find the 8th term of an arithmetic sequence, you can use the formula:
an = a1 + (n-1)d
where:
an = the nth term
a1 = the first term
d = the common difference between terms
n = the term number
In this case, a1 = 4 and d = 5. We need to find the 8th term, so n = 8.
Plugging the given values into the formula:
a8 = 4 + (8-1)5
Simplifying the equation:
a8 = 4 + 7 * 5
= 4 + 35
= 39
Therefore, the 8th term of the arithmetic sequence is 39.
To find the 8th term of an arithmetic sequence, you can use the formula:
an = a1 + (n - 1)d,
where:
- an represents the nth term of the sequence,
- a1 denotes the first term of the sequence, and
- d is the common difference between consecutive terms.
In this case, a1 = 4 and d = 5. We want to find the 8th term, so n = 8.
Plugging these values into the formula, we get:
a8 = 4 + (8 - 1) * 5
= 4 + 7 * 5
= 4 + 35
= 39.
Therefore, the 8th term of the arithmetic sequence is 39.
Well first off you need to know how to set up the equation. That equation being: an = a1 + (n - 1) d. Now we can just plug in our given numbers. (remember the nth term is 8) So, a8 = 4 + (8 - 1) 5. Simplify using PEMDAS.
First add what's in the parenthesis: a8 = 4 + (7) * 5 4 + 35.
Then multiply: a8 = 4 + 35.
Lastly add: a8 = 39.
So the 8th term of the arithmetic sequence is 39