Select the letter that best answers each question. Use the formula for the area of a trapezoid to help you solve the problems.
1.What is the area of the trapezoid? (1 point)
14cm on top
10cm in the mid
and 21cm on the bottom
A.175 cm
B.350 cm
C.735 cm
2. Find the area of the trapezoid. (1 point)
8mm on top
5mm on the left
and 12mm on the bottom
A.100mm
B.25mm
C.50mm
3. What is the area of the trapezoid? (1 point)
17in on the top
8in in the mid
and 10in on the bottom
A. 88in
B. 108in
C. 216in
4. Find the area of the trapezoid. (1 point)
0.4m on the left
1.2m on the right
and 0.6m on the bottom
A. 0.48m
B. 0.24m
C. 48
5. What is the area of the trapezoid? (1 point)
8yd on the top
17yd on the right
9yd in the mid
and 19yd on the bottom
A. 229.5yd
B. 207yd
C. 121.5yd
i need help with this
1A = 175
2A = 50
3A = 108
4A = ?
5A = I think it 121 (not sure)
P.s. I have a special calculator so the answers are correct!! Also, I'm sooooo sorry I didn't answer D: I had to eat
Hope this helps :)
Is this from Connexus? If it is, can you tell me the name of the quiz or quick check and what Unit it is?
Plus what grade?
it is from connexus and 6th, Its from
Essential Math 6 B - Mid-Unit Review
Area of Rectangles and Squares, Area of Parallelograms and Triangles, and Metric Units, Perimeter, and Area Problem Solving
unit 3
thanks that helped alot
:DDD Sorry i was too late
1.A
2.C
3.B
4.A
5.C
Hope this helps!
🤗
I have 7 questions and 20 missed assignments in trying to finish them before my mom wakes up. Does anyone have to answers to Areas of Composite Figures Practice??
To find the area of a trapezoid, you can use the formula:
Area = (1/2) * (base1 + base2) * height
1. For the first problem, we have:
Base1 = 14 cm, Base2 = 21 cm, and height = 10 cm
Plugging those values into the formula, we get:
Area = (1/2) * (14 + 21) * 10
Area = (1/2) * 35 * 10
Area = 175 cm
Therefore, the answer is A. 175 cm.
2. For the second problem, we have:
Base1 = 8 mm, Base2 = 12 mm, and height = 5 mm
Plugging those values into the formula, we get:
Area = (1/2) * (8 + 12) * 5
Area = (1/2) * 20 * 5
Area = 50 mm
Therefore, the answer is C. 50 mm.
3. For the third problem, we have:
Base1 = 17 in, Base2 = 10 in, and height = 8 in
Plugging those values into the formula, we get:
Area = (1/2) * (17 + 10) * 8
Area = (1/2) * 27 * 8
Area = 108 in
Therefore, the answer is B. 108 in.
4. For the fourth problem, we have:
Base1 = 0.4 m, Base2 = 0.6 m, and height = 1.2 m
Plugging those values into the formula, we get:
Area = (1/2) * (0.4 + 0.6) * 1.2
Area = (1/2) * 1 * 1.2
Area = 0.6 m
Therefore, the answer is B. 0.24 m.
5. For the fifth problem, we have:
Base1 = 8 yd, Base2 = 19 yd, and height = 9 yd
Plugging those values into the formula, we get:
Area = (1/2) * (8 + 19) * 9
Area = (1/2) * 27 * 9
Area = 121.5 yd
Therefore, the answer is C. 121.5 yd.
Make sure to double-check all your calculations to ensure accuracy.
These are all the same problem.
A trapezoid with bases B and b and height h has area A = (b+B)/2 * h
the first trapezoid has area (14+21)/2 * 10 = 175
Looks like you need to review properties of trapezoids.