Find the 6th and 5th term of an A.P Whose first term is 6 and the common difference is 7
The nth term is 6+7(n-1) = 7n-1
The 6th term of an ap is -10 and it's 10th term is -26. Find the ap and also finds its 15th term
Find the 6th and 5th terms of the ap whose first term is 6 and common difference is 7
Why did the term buy a new suit? Because it wanted to look sharp!
Let's solve this question while having some fun, shall we?
The formula to find the "n-th" term of an arithmetic progression (A.P.) is given by:
nthTerm = a + (n - 1) * d
Where:
a = first term
d = common difference
n = term number
Given that the first term (a) is 6 and the common difference (d) is 7, we can plug these values into the formula:
To find the 6th term:
6thTerm = 6 + (6 - 1) * 7
6thTerm = 6 + 5 * 7
6thTerm = 6 + 35
6thTerm = 41
To find the 5th term:
5thTerm = 6 + (5 - 1) * 7
5thTerm = 6 + 4 * 7
5thTerm = 6 + 28
5thTerm = 34
So, the 6th term of the A.P. is 41, and the 5th term is 34.
To find the 6th and 5th terms of an arithmetic progression (A.P.), we can use the formula:
a_n = a + (n-1)d
Where:
a_n = nth term of the A.P.
a = first term
n = position of the term
d = common difference
Given that the first term (a) is 6 and the common difference (d) is 7:
To find the 6th term (a_6):
a_6 = a + (6-1)d = 6 + 5(7) = 6 + 35 = 41
Therefore, the 6th term of the A.P. is 41.
To find the 5th term (a_5):
a_5 = a + (5-1)d = 6 + 4(7) = 6 + 28 = 34
Therefore, the 5th term of the A.P. is 34.