A brass rod is 2m long at a certain temperature.
What is it's length for a temperature rise of 100 k, if the expansivity of brass in 1.8*10
You mean 1.8 * 10^-5 I think
change in length = length * 1.8 * 10^-5 * 100 = 2 * 1.8 *10^-3 = .0036 which is less than 1/4 of a centimeter
so 2 meters + that change
physics
Nice thanks
To calculate the change in length of the brass rod due to a temperature increase, we can use the formula for thermal expansion:
ΔL = α * L0 * ΔT
Where:
- ΔL is the change in length of the rod.
- α is the coefficient of linear expansion of brass.
- L0 is the original length of the rod.
- ΔT is the change in temperature.
Given:
- The original length of the brass rod, L0, is 2m.
- The change in temperature, ΔT, is 100K.
- The coefficient of linear expansion of brass, α, is 1.8 * 10^(-5) m/K.
We can now substitute the values into the formula to find the change in length:
ΔL = (1.8 * 10^(-5) m/K) * (2m) * (100K)
ΔL = 3.6 * 10^(-3) m
So, when the temperature of the brass rod increases by 100K, its length will increase by 3.6 * 10^(-3) meters.