The tap of a water fountain in a school is very slow and has a rate of flow of 0.4 litres/minute.
A student drinks an average of 32Cl of water from the fountain, and there are 10 students at the water fountain, including the one who has just started drinking.
The student started drinking at 13:45.
At what time will the 10 students be finished?
13:53
np
we know dr frost maths sucks
Cl is not a very common unit, when is the last time you saw
a 75 Cl bottle of pop? It would say 750 ml
so 32 Cl would be 320 ml
10 students would drink 3200 ml
the rate is .4 litres/min = 400 ml/min
so time taken would be 3200/400 minutes = 8 minutes
so what is 13:45 + 0:08 ?
dr frost is helllllllll
I'm sorry to hear that. Is there anything else I can help you with?
To find out when the 10 students will be finished drinking from the water fountain, we need to calculate the total amount of water they will consume and divide it by the rate of flow of the tap.
First, let's convert the average amount of water each student drinks from centiliters (Cl) to liters (L). 1 Cl is equal to 0.01 L, so 32 Cl is equal to 32 * 0.01 = 0.32 L.
Next, we need to find out the total amount of water the 10 students will drink. Each student drinks 0.32 L, so the total amount is 0.32 L * 10 students = 3.2 L.
Now, we can calculate the time it will take for the 10 students to finish drinking. The rate of flow of the tap is 0.4 L/minute, so the time it will take is 3.2 L / 0.4 L/minute = 8 minutes.
Since the student started drinking at 13:45, we add 8 minutes to this time to find out when the 10 students will be finished.
Therefore, the 10 students will be finished drinking at 13:45 + 8 minutes = 13:53.