Nina had 1/7 as many cakes to sell as Belle. The two friends decided to share the work evenly. To do that, Belle had to give 15 cakes to Nina. What was the total number of cakes the two friends had to sell?
b-15 = b/7 + 15
b = 35
so nina had 5, and together they had 40
check:
35-15 = 5+15
To find the total number of cakes the two friends had to sell, we can start by figuring out how many cakes Belle had initially.
Let's assume the number of cakes Belle had is represented by 'x'. According to the problem, Nina had 1/7 as many cakes to sell as Belle, which means Nina had (1/7)*x cakes.
Now, it is given that Belle had to give 15 cakes to Nina in order to share the work evenly. So, after giving 15 cakes to Nina, the number of cakes Belle had left is (x - 15).
Since they decided to share the work evenly, the number of cakes they had to sell is the sum of Belle's remaining cakes and Nina's cakes, which is (x - 15) + (1/7)*x.
Now we can set up an equation to solve for 'x':
(x - 15) + (1/7)*x = total number of cakes
Simplifying the equation:
(8/7)*x - 15 = total number of cakes
To solve for 'x', we need to know the value of the total number of cakes. If you provide that information, we can solve the equation to find the total number of cakes the two friends had to sell.
x = number of cakes Nina would have after getting the 15. Multiply that by 2 for both of them.
6/7x = 15
n = b/7
n + 15 = b - 15 or n = b - 30
so
b -30 =b/7
7 b - 210 = b
6 b = 210
b = 35
n = b - 30 = 5
35 + 5 = ?
number of cakes that Nina has = x
number of cakes that Belle has = 7x
Belle gives 15 to Nina, Belle now has 7x - 15
Nina has x + 15
we are told that 7x - 15 = x + 15
6x =30
x = 5
total cakes = x + 7x = 8x = 40