calc/physics

A force of 250 N is required to stretch a spring 5m from rest. Using Hooke's law, F=kx, how much work, in joules, is required to stretch the spring 7m from rest?

The energy required scales with x^2.
Multiply 250 J by (7/5)^2.

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asked by Mischa
  1. 350 J

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    posted by derek

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