A 0.41kg football that is initially at rest acquires a velocity of 35m/s when it is kicked. If the kicker's boot remains in contact with the ball for 0.08s, what is the average force of the kick?
To find the average force of the kick, we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration. In this case, the football's mass is given as 0.41 kg and we need to find its acceleration.
To find the acceleration, we can use the following kinematic equation:
v = u + at
Where:
v = final velocity = 35 m/s
u = initial velocity = 0 m/s (since the football is initially at rest)
a = acceleration
t = time = 0.08 s
Rearranging the equation to solve for acceleration a, we have:
a = (v - u) / t
Substituting the given values, we get:
a = (35 m/s - 0 m/s) / 0.08 s
a = 437.5 m/s²
Now that we have the acceleration, we can calculate the average force of the kick using Newton's second law:
F = m * a
Substituting the given values, we have:
F = 0.41 kg * 437.5 m/s²
F = 179.375 N
Therefore, the average force of the kick is approximately 179.375 Newtons.