A bag contains only red, green, brown and yellow marbles. The probabilities of selecting each colour are Green is 0.1, Brown is 0.72 what is the probabilities of choosing Yellow and Red if they are the same value?
probability of choosing other than green or brown
= 1 -.1 - .72 = .18
so .18 * .18 if there are LOTs of marbles in there so the probability does not change when you remove one.
To find the probability of choosing yellow and red marbles, we need to know the probability of selecting each color, excluding green and brown, as they have already been given.
Let's assume the probability of selecting yellow and red marbles are equal, denoted by 'P(yellow)' and 'P(red)'. Since all the probabilities must sum up to 1, we can set up an equation:
P(green) + P(brown) + P(yellow) + P(red) = 1
Given that P(green) = 0.1 and P(brown) = 0.72, the equation becomes:
0.1 + 0.72 + P(yellow) + P(red) = 1
Simplifying the equation, we can rewrite it as:
P(yellow) + P(red) = 1 - 0.1 - 0.72
P(yellow) + P(red) = 0.18
Since the probabilities of choosing yellow and red are equal, we can represent them as 'P(yellow) = P' and 'P(red) = P'. Substituting these values into the equation, we get:
P + P = 0.18
2P = 0.18
P = 0.09
Therefore, the probabilities of choosing yellow and red marbles are both 0.09.