a car travellind due north at 60 km/hr increased its velocity to 80 m/s due north in 20 second.draw the spped adainsts time graph
60 km/hr * 1000m/km * 1hr/3600s = 16.67 m/s
a = (80-16.67)/20 = 3.17 m/s^2
This is the slope of the graph of the velocity
oh no
To draw the speed against time graph, we first need to convert the units of velocity to be consistent.
Given: Car's initial velocity (v1) = 60 km/hr
Car's final velocity (v2) = 80 m/s
Time (t) = 20 seconds
Step 1: Convert initial velocity from km/hr to m/s.
To do this, we use the conversion factor: 1 km/hr = 0.27778 m/s
60 km/hr * 0.27778 m/s = 16.66666 m/s ≈ 16.67 m/s
So, the car's initial velocity (v1) is approximately 16.67 m/s.
Step 2: Plot the points on the graph.
The first point will be (0, 16.67) since at the start time (t = 0 seconds), the car's velocity is 16.67 m/s.
The second point will be (20, 80) since at 20 seconds, the car's velocity increased to 80 m/s.
Step 3: Connect the two points with a straight line.
This straight line represents the speed against time graph.
The graph will have time (t) on the x-axis and speed (v) on the y-axis.