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Peter has money in two savings accounts. One rate is 9% and the other is 11%. If he has $200 more in the 11% account and the total interest is $68, how much is invested in each savings account?

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  1. Let x represent mount at 9%
    Let x + 200 represent amount at 11%
    Total interest earned is 68$
    0.09x + 0.11 (x + 200) = 68
    0.09x + 0.11x + 22 = 68
    0.2x + 22 = 68
    0.2x + 22 - 22 = 68 - 22
    0.2x = 46
    0.2x / 0.2 = 46 / 0.2
    x = $230 is amount at 9%
    Amount at 11%= 230 + 200 = $430

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