How much heat has to be added to change 0.500 kg ice from -10C completely to a steam of 110C. The specific heat of ice, water and steam is 2090 J/kg ⋅K, 4186 J/kg⋅K, 2010 J/kg ⋅K respectively. Given that the heat J/kg, the heat of J/kg. Draw of fusion for ice is 3.34×10^5 vaporization for water is 2.26×10^6 the heat curve that shows the process as thermal energy is added to the system. Calculate the heat added to each five steps of this process.

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  1. answer please

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  2. help:(

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  3. helppppp

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  4. heat ice

    melt ice ... heat of fusion * mass

    heat water

    boil water ... heat of vaporization * mass

    heat steam

    for the three heating steps ... mass * specific heat * Δt

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  5. can you plug in the numbers please. its kinda confusing than you

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