A cone and a cylinder have a diameter of 6 inches and a height of 11 inches . Find the volume of each shape to the nearest tenth . Use 3.14 for Pi
v=pi r/2 h
To find the volume of both the cone and the cylinder, we'll need to use the formulas for volume of a cone and volume of a cylinder.
First, let's find the volume of the cone:
The formula for the volume of a cone is V = (1/3) * π * r^2 * h, where π is approximately 3.14, r is the radius, and h is the height.
Given that the diameter of the cone is 6 inches, we can find the radius by dividing the diameter by 2: 6 ÷ 2 = 3 inches.
Using the formula, we substitute the values we have:
V_cone = (1/3) * 3.14 * 3^2 * 11
= (1/3) * 3.14 * 9 * 11
≈ 102.15
So, the volume of the cone is approximately 102.15 cubic inches.
Next, let's find the volume of the cylinder:
The formula for the volume of a cylinder is V = π * r^2 * h, where π is approximately 3.14, r is the radius, and h is the height.
Again, we know that the diameter of the cylinder is 6 inches, so the radius is 3 inches.
Using the formula, we substitute the values we have:
V_cylinder = 3.14 * 3^2 * 11
≈ 301.38
So, the volume of the cylinder is approximately 301.38 cubic inches.
area of base B = πr^2
for the volumes,
cylinder = Bh
cone = 1/3 Bh