# Calc 121

Okay, how would you go about finding the area of a curve from 1 to 4, when y=2x+(2/(x^2))?? It's not like the problem I asked before because here, you cannot use substitution. I tried using 2x for u and x^2 for du but it won't simplify into a ln problem or anything that I can work with.

Also, how do you take the derivative/anti-derivative of a fraction like: (3x^2)/(2)?

I really appreciate the help!

The indefinite integral of that function is
x^2 -2/x. Calculate the value of that function at x=4 and subtract the value at x=1. That will be the area above the x-axis.

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