Use the Law of Sines to find the missing side of the triangle.
Find b.
A. 70.1
B. 43.8
C. 57.1
D. 31.5
Law of Sines and Cosines Quiz Part 1
A spotlight is mounted on a wall 7.4 feet above the floor in an office building. It is used to light a door 9.3 feet from the wall. To the nearest degree, what is the angle of depression from the spotlight to the bottom of the door?
Answer: A.39°
A tree that is 10 yards tall casts a shadow 14 yards long. Find the angle of elevation from the tip of the shadow to the top of the tree. Round to the nearest degree.
Answer: B.36°
Use the Law of Sines to find the missing side of the triangle.
Find b.
Answer: B.43.8
For a triangle, ABC, find the measure of segment AB given m∠A = 55°, m∠B = 44°, and b = 68.
Answer: B.96.68
Use the Law of Cosines to solve the problem.
On a baseball field, the pitcher’s mound is 60.5 feet from home plate. During practice, a batter hits a ball 216 feet. The path of the ball makes a 34° angle with the line connecting the pitcher and the catcher, to the right of the pitcher’s mound. An outfielder catches the ball and throws it to the pitcher. How far does the outfielder throw the ball?
Answer: C.169.3 ft
In triangle STU, s = 9 cm, t = 15 cm, and measure of angle upper U equals 37 degrees. Find u.
Answer: C.9.5 cm
7) Find the value of x. Round to the nearest tenth. The diagram is not drawn to scale.
tan(35)=x/12
.7=x/12
12*.7=x
Answer: x=8.4
8) Find the value of x. Round the length to the nearest tenth. The diagram is not drawn to scale.
2879.4
sin=opposite/hypotenus
sin 10 degrees=500/x
x(sin 10 degrees)=500
0.1736481x=500
x=500/0.1736481
Answer: x= 2879.4 meters
so we all from connexus :,)) ??
The answer is b 43.8
im an honors student, these were my assignments for this lesson:
the practice test:
1. 43.8
2. 58.8
3. 169.3 ft
4. 33.9
5. 44.7
6. 9.5cm
and for the quiz:
1. 96.68
2. 58.34
3. 39
4. 48.4
5. 70.0
6. 95
7. 169.3
8. this one is written but i think you can just copy and paste this equation:
cos(10) = 500/x
x = 500/cos(10)
x = 507.7
it is indeed b. 43.8
We sure are zeke=monke 😢
I mean at least I am, whazzaaaap
deku is right
now how bout part two?😃
Shhhhhh
Deku is 100% right for the multiple choice questions.
. is right!!!
deku is right ty!!!
Deku u r the goat
yo
. is 100% correct.
deku is completely correct!!
do y’all know the last one for part 2
A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given. a. Find BC, the distance from Tower 2 to the plane, to the nearest foot. b. Find CD, the height of the plane from the ground, to the nearest foot.
Part two isn’t skipped for y’all😗
For thoes of you stuck on the part 2.
A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given.
If CD=h and BC=x, then
h/x = tan24°
h/(x+7600) = tan16°
or,
h = 0.4452x
h = 0.2867x + 2179.2649
0.4452x = 0.2867x + 2179.2649
BC = x = 13750
CD = h = 6121
A ship travels due west for 94 miles. It then travels in a northwest direction for 119 miles and ends up 173 miles from its original position. To the nearest tenth of a degree, how many degrees north of west (x) did it turn when it changed direction? Show your work
a=94
b=119
c=173
173^2 = 94^2 + 119^2 - 2 x 94 x 119
22327=6932
6932/22327
c=108
The answer is x = 45.2 degrees.
To find x, first draw a diagram and label it. Let the starting point be O and let the ship end up at point P. Let the angle between the initial westward direction and the northwest direction be y degrees. Then, the angle between the northward direction and the northwest direction is (90 - y) degrees.
Using the Law of Cosines, we can solve for y:
c^2 = a^2 + b^2 - 2ab cos(C)
173^2 = 94^2 + 119^2 - 2(94)(119)cos(y)
cos(y) = (94^2 + 119^2 - 173^2)/(2(94)(119))
cos(y) = 0.511
y = 59.3 degrees
To find x, we subtract the angle between the northwest direction and the initial westward direction (90 - y) from 90 degrees:
x = 90 - (90 - y)
x = y
x = 59.3 degrees, rounded to the nearest tenth.
Thanks Bot
You're welcome! Let me know if you have any other questions.
Your gonna have to look how to do it @urmom sadly
no idea, since you tell us nothing about your triangle. But
a/sinA = b/sinB = c/sinC