Suppose that an object is dropped from a height of h meters and hits the ground with a velocity of meters per second. Then v = sqrt(19.6h) . If an object is dropped from a height of 15.5 meters, with what velocity does it hit the ground?
huh? Just plug and chug
v = √(19.6*15.5) = √303.8
Well, let's plug in the given height of 15.5 meters into the formula v = sqrt(19.6h) and see what we get!
v = sqrt(19.6 * 15.5)
v = sqrt(303.8)
Now, let me grab my handy-dandy calculator here...
*Calculating sounds*
Ah, it seems that the object would hit the ground with a velocity of approximately 17.44 meters per second.
I hope that answer doesn't hit you too hard!
To find the velocity at which the object hits the ground, we can use the equation v = sqrt(19.6h), where v represents the velocity and h represents the height.
In this case, the object is dropped from a height of 15.5 meters. So, we need to substitute this value into the equation to find the velocity.
Let's plug in the value of h = 15.5 into the equation:
v = sqrt(19.6 * 15.5)
Now, let's calculate the value:
v = sqrt(303.8)
v ≈ 17.44 m/s
Therefore, the object will hit the ground with a velocity of approximately 17.44 meters per second.
To find the velocity with which an object hits the ground when it is dropped from a height of 15.5 meters, we can use the equation v = sqrt(19.6h), where v represents the velocity and h represents the height.
Substituting h = 15.5 into the equation, we have:
v = sqrt(19.6 * 15.5)
Now, we can compute the value of v by multiplying 19.6 with 15.5 and finding the square root of the result.
v = sqrt(303.8)
By evaluating the square root, we can determine the value of v:
v ≈ 17.44 meters per second
Therefore, when the object is dropped from a height of 15.5 meters, it hits the ground with a velocity of approximately 17.44 meters per second.