PLS HELP!!! (not multiple choice)

If a car travels at a constant rate of speed, the distance that it travels varies directly as time. If a car travels 75 miles in 2.5 hours, it will travel 110 feet in 2.5 seconds.

a. Find the constant of variation in miles per hour
b. Draw a graph that compares the distance that the car travels in miles to the number of hours traveled. Let the horizontal axis represent minutes and the vertical axis represents characters.
c. Find the constant of variation in feet per second.
d. Draw a graph that compares the distance the car travels in feet to the number of seconds traveled.

Go to the first time you posted this question. Or any of the other times when someone responded. What do you still not get?

Hii! People keep responding with (A) but the question is a multi-step problem and a,b,c,and d are asking different things.

a. To find the constant of variation in miles per hour, we can use the formula:

Constant of variation = distance / time

In this case, the car travels 75 miles in 2.5 hours. Plugging these values into the formula, we get:

Constant of variation = 75 miles / 2.5 hours
Constant of variation = 30 miles per hour

Therefore, the constant of variation in miles per hour is 30.

b. To draw a graph that compares the distance the car travels in miles to the number of hours traveled, we can create a Cartesian coordinate system. Let the horizontal axis represent hours and the vertical axis represent miles.

Plot the point (2.5, 75) on the graph, indicating that the car travels 75 miles in 2.5 hours. Connect this point with a straight line to the origin (0,0).

c. To find the constant of variation in feet per second, we can use the same formula as in part a:

Constant of variation = distance / time

In this case, the car travels 110 feet in 2.5 seconds. Plugging in these values, we get:

Constant of variation = 110 feet / 2.5 seconds
Constant of variation = 44 feet per second

Therefore, the constant of variation in feet per second is 44.

d. To draw a graph that compares the distance the car travels in feet to the number of seconds traveled, we can use the same Cartesian coordinate system. Let the horizontal axis represent seconds and the vertical axis represent feet.

Plot the point (2.5, 110) on the graph, indicating that the car travels 110 feet in 2.5 seconds. Connect this point with a straight line to the origin (0,0).