The numerator of a fraction is 3 more than the denominator. If both the numerator and the denominator are increased by 3. Find the fraction.
n = numerator
d = denominator
The numerator of a fraction is 3 more than the denominator means:
n = d + 3
If both the numerator and the denominator are increased by 3 the fraction will be:
( n - 3 ) / ( d - 3 ) = ( d + 3 - 3 ) / ( d - 3 ) = d / ( d- 3 )
Thank you so much very big help 😊
The denominator of a fraction in the simplest form is greater than the numerator by 1. If 4 is added to the numerator, and 3 is subtracted from the denominator, then the fraction itself is increased by 2 1/6 . Find the original
To solve this problem, let's start by assigning variables. Let's say the denominator of the fraction is "x".
According to the problem, the numerator is 3 more than the denominator. So, the numerator can be expressed as "x + 3".
Now, we need to find the fraction when both the numerator and the denominator are increased by 3.
The new numerator would be "x + 3 + 3", which simplifies to "x + 6".
The new denominator would be "x + 3 + 3", which also simplifies to "x + 6".
Therefore, the fraction can be written as (x + 6)/(x + 6).
But notice that the numerator "x + 6" and denominator "x + 6" are the same. So, the fraction simplifies to 1.
Hence, the fraction is 1.