¡¡ in this problem the car is ’rolling off’ a table.
So the initial Y/Vertical velocity (Viy) is zero
(0). HINT: Solve for ”time” first (using the
formula t=sqrt(2*dy/g).¿¿
A toy car runs off the edge of a table that
is 1.191 m high. The car lands 0.302 m from
the base of the table.
How long does it take for the car to fall?
The acceleration due to gravity is 9.8 m/s^2.
Answer in units of s.
What is the horizontal velocity of the car?
Answer in units of m/s.
To solve this problem, we can use the equations of kinematics. First, let's find the time it takes for the car to fall using the formula:
t = sqrt(2 * dy / g)
where:
t is the time taken to fall,
dy is the vertical distance the car falls (1.191 m in this case), and
g is the acceleration due to gravity (9.8 m/s^2).
Substituting the values into the equation:
t = sqrt(2 * 1.191 / 9.8)
Evaluating this expression:
t = 0.491 s (rounded to three decimal places)
So, it takes approximately 0.491 seconds for the car to fall.
Next, let's find the horizontal velocity of the car. Since the horizontal velocity remains constant during the fall, we can use the horizontal distance the car lands (0.302 m) and the time it takes to fall (0.491 s) to find the horizontal velocity.
Horizontal velocity (Vix) = horizontal distance / time
Vix = 0.302 m / 0.491 s
Evaluating this expression:
Vix = 0.615 m/s (rounded to three decimal places)
Therefore, the horizontal velocity of the car is approximately 0.615 m/s.