The vertices of a triangle are P(1,4), Q(-7,7), and R(2,-6). Name the vertices of R y=x(🔼PQR).
A. P’(4,-1), Q’(7,7), R’(-6,-2)
B. P’(-4,1), Q’(-7,-7), R’(6,2)
C. P’(4,1), Q’(-7,7), R’(-6,2)
D. P’(-4,-1), Q’(-7,7), R’(6,-2)
To find the vertices of R y=x(🔼PQR), we need to find the image of point R(2, -6) under the transformation y = x.
In the transformation y = x, the x-coordinate becomes the new y-coordinate, and the y-coordinate becomes the new x-coordinate. Therefore, the transformation swaps the x and y coordinates of a point.
Applying this transformation to point R(2, -6), we get the new coordinates as (y, x) = (-6, 2).
Therefore, the vertices of R y=x(🔼PQR) are P(1, 4), Q(-7, 7), and R'(-6, 2).
Among the given answer choices, C. P’(4,1), Q’(-7,7), R’(-6,2) matches the calculated coordinates.
No idea what 🔼 means, but it looks like a reflection or two is involved.
across the x-axis: (x,y)→(x,-y)
across the y-axis: (x,y)→(-x,y)