Lesson 8: Applications of Proportions Unit Test CE 2015
Algebra Readiness (Pre-Algebra) A Unit 5: Applications of Proportions
WHAT ARE THE ANSWERS!?!
PLEASE HELP
guys your in connexus too 💀💀
1. B(3:1)
2. A(5.25)
3. B(37.5 inches)
4. D(31.27 miles/hour)
5. C(6.3 inches/month)
6. B($274.07)
7. D(40 inches)
8. B(24 inches)
9. D(112 ft)
10. D(336 m^2)
11. C(scale factor 3; enlargement)
12. B(1/2)
13. D(24 ft x 21 ft)
14. A(2 in x 3 in)
15. B(31.25 miles)
16. B(8 feet)
17. i got this one wrong so sorry
18. V(12,4),W(-4,8),X(-6,-4), Y(6,-10)
19. they are similar but you write why they are
i hope this helped plz dont tell on me i just want to help ðŸ˜
I need the actual answers
DUde idk I NEED HELP WITH IT TOO
1-c
2-a
3-b
4-b
5-c
6-b
7-c
8-b
9-d
10-c
11-b
12-d
13-d
14-c
15-a
16-b
On your own for the short answer questions
they weren't :'0
idk im on it it 2
bruh I'm failing algebra so bad I hope these answers r right lmaoo :')
HELP PLZ
urrobloxgf420 what were the right answers then
If you put the question with the answer we would actually get right answers because questions are in diffrent spots for everyone
THATS FOR THE INFO MRS RIPLEY WE CAN JUST LIST 3 SETS XDDDDD
fakeee
The coordinates of quadrilateral these WXY are given below find coordinates of its image after a dilation with the given scale factor be parentheses six, two parentheses, W parentheses -2, four parentheses, X parentheses -3, -2 parentheses, Y parentheses three, -5 parentheses, scale factor of two
Exactly Furipley-
For anyone who sees this please start typing out the questions and the answers and not the letters.. Please know that it's a common trick for teachers at connexus to have different versions of the test where they either add more questions, change them up a bit, or switch the places of the answers or questions. To prevent people from failing please start typing those out :(
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Use cross products to demonstrate whether or not the two ratios are equivalent:
4/6 and 14/21
The size of a rectangle are confused by a scale factor of four the perimeter of the smaller rectangle is 20 cm what is the perimeter of the larger rectangle 1.320 cm 2. 80 cm 3. 120 cm 4. 60 cm
To find the perimeter of the larger rectangle, we can use the concept of scale factor.
If the scale factor is 4, it means the dimensions of the larger rectangle are four times larger than the dimensions of the smaller rectangle.
Let's assume the perimeter of the smaller rectangle is represented by P.
Since the scale factor is 4, the dimensions of the larger rectangle will be 4 times larger than the dimensions of the smaller rectangle. This means the perimeter of the larger rectangle will also be 4 times larger than the perimeter of the smaller rectangle.
Therefore, the perimeter of the larger rectangle can be calculated as 4P.
Given that the perimeter of the smaller rectangle is 20 cm, we can substitute P = 20 into the equation to find the perimeter of the larger rectangle.
Perimeter of the larger rectangle = 4P = 4(20) = 80 cm
So, the perimeter of the larger rectangle is 80 cm.
The correct answer is 2. 80 cm.
The right triangle has an area 21m2 of the dimensions of a triangle are increased by a scale factor of four what is the area of the new triangle 1.42m2 2.84m2. 3.168m2. 4.336m2
To solve this problem, let's start by finding the dimensions of the original triangle.
The area of a right triangle is given by the formula: (base * height) / 2.
Let's assume the base of the original triangle is represented by b and the height is represented by h.
Area of the original triangle = (b * h) / 2
Given that the area of the original triangle is 21 m^2, we can substitute this into the equation:
21 = (b * h) / 2
Now, let's solve for the dimensions of the original triangle:
(b * h) = 21 * 2
b * h = 42
Since we don't have specific values for the base and height, we cannot determine their individual values. However, we can proceed to find the area of the new triangle when the dimensions are increased by a scale factor of four.
When the dimensions are increased by a scale factor of four, the new base and height will be 4 times larger than the original base and height.
Let's define the new base as B and the new height as H.
B = 4b (new base is 4 times larger than the original base)
H = 4h (new height is 4 times larger than the original height)
To find the area of the new triangle, we can use the formula:
Area of the new triangle = (B * H) / 2
Substituting the values of B and H:
Area of the new triangle = (4b * 4h) / 2 = (16bh) / 2 = 8bh
Since we know that the area of the original triangle is 21 m^2, we can substitute b * h = 42 into the equation:
Area of the new triangle = 8 * 42 = 336 m^2
Therefore, the area of the new triangle is 336 m^2.
The correct answer is 4. 336 m^2.
Quadrilateral PQRS was deleted to produce quadrilaterals PQRS on the grid below what was the apparent scale factor of the dilation used to produce quadrilaterals PQRS 3/4 1/2 2. 4
To determine the apparent scale factor of the dilation used to produce quadrilaterals PQRS, we need to compare the corresponding side lengths of the original and dilated quadrilaterals.
Let's examine the sides of quadrilateral PQRS.
Assuming the side lengths of quadrilateral PQRS are represented by p, q, r, and s, and the corresponding side lengths of the dilated quadrilateral PQRS are represented by P, Q, R, and S, respectively.
To find the scale factor, we can calculate the ratio of the corresponding side lengths:
Scale factor = P/p = Q/q = R/r = S/s
Since the scale factor is the same for all corresponding side lengths, we only need to compare one pair of corresponding side lengths.
If we compare side PQ (length p) and side PQ' (length P) on the coordinate grid, we can determine the scale factor.
Given the answer choices provided, we can calculate the ratio of P/p for each option:
1. Scale factor of 3/4: P/p = 3/4 ≠PQ' / PQ
2. Scale factor of 1/2: P/p = 1/2 ≠PQ' / PQ
3. Scale factor of 2: P/p = 2 = PQ' / PQ
Since the ratio of PQ' to PQ is equal to the scale factor of 2, the correct answer is 3. The apparent scale factor of the dilation used to produce quadrilaterals PQRS is 2.
Note that without specific side lengths or more information, we can only determine the apparent scale factor based on the given options and the comparison of corresponding side lengths.
The width of the picture is 20 cm using a color copier you reduce the width of the picture to 5 cm what is the scale factor of the dilation 5. 1/5 .4 or 1/4
To determine the scale factor of the dilation used to reduce the width of the picture from 20 cm to 5 cm, we can calculate the ratio of the new width to the original width.
Scale factor = New width / Original width
In this case, the new width is 5 cm and the original width is 20 cm.
Scale factor = 5 cm / 20 cm = 1/4
Therefore, the scale factor of the dilation used to reduce the width of the picture is 1/4.
The correct answer is 4. 1/4.
On a given blueprint 1 inch equals Chelsea if the dimensions of a re-creation room on the blue pit are 2 inches times 1.75 inches what are its actual measurements 1 foot times 12‘6 feet times7 feet 22×18‘24 feet times 21 feet
To determine the actual measurements of the re-creation room, we need to use the scale factor given in the blueprint.
The scale factor given is 1 inch equals Chelsea. However, it seems like there may be a typo or an error in the question, as "Chelsea" is not a unit of measurement.
If we assume that "Chelsea" should be "1 inch equals 1 foot" (1 inch = 1 ft), we can proceed with the calculation.
The dimensions of the re-creation room on the blueprint are 2 inches by 1.75 inches.
To find the actual measurements, we can multiply the dimensions on the blueprint by the scale factor.
Actual length = 2 inches * 1 ft = 2 ft
Actual width = 1.75 inches * 1 ft = 1.75 ft
Therefore, the actual measurements of the re-creation room are 2 ft by 1.75 ft.
The correct answer is 1 foot times 12.6 feet.
Using a scale factor of 1 inch equal 16 feet, what are the blueprint dimensions of a room that is 20 feet X 28 feet 1.5 inches X 2.5 inches 1.25 inches X 2.25 inches 1.25 inches X1.75 inches 1.5 inches X1.75 inches
To determine the blueprint dimensions of a room given a scale factor of 1 inch equal to 16 feet, we need to divide the actual measurements by the scale factor.
The actual dimensions of the room are 20 feet by 28 feet.
Blueprint length = 20 feet / 16 = 1.25 feet
Blueprint width = 28 feet / 16 = 1.75 feet
Therefore, the blueprint dimensions of the room are 1.25 feet by 1.75 feet.
For the additional dimensions you provided:
1.5 inches X 2.5 inches
Blueprint length = 1.5 inches / 16 = 0.09375 feet
Blueprint width = 2.5 inches / 16 = 0.15625 feet
1.25 inches X 2.25 inches
Blueprint length = 1.25 inches / 16 = 0.078125 feet
Blueprint width = 2.25 inches / 16 = 0.140625 feet
1.25 inches X 1.75 inches
Blueprint length = 1.25 inches / 16 = 0.078125 feet
Blueprint width = 1.75 inches / 16 = 0.109375 feet
1.5 inches X 1.75 inches
Blueprint length = 1.5 inches / 16 = 0.09375 feet
Blueprint width = 1.75 inches / 16 = 0.109375 feet
Therefore, the blueprint dimensions for the given additional dimensions are:
- 1.5 inches X 2.5 inches: 0.09375 feet by 0.15625 feet
- 1.25 inches X 2.25 inches: 0.078125 feet by 0.140625 feet
- 1.25 inches X 1.75 inches: 0.078125 feet by 0.109375 feet
- 1.5 inches X 1.75 inches: 0.09375 feet by 0.109375 feet
The scale of a mass is 1/8 equals 25 miles how many miles does 1.25 inches represent 25 miles 31.25. 62.5 miles 49.25 miles
To find out how many miles 1.25 inches represents in the given scale, we can set up a proportion.
The scale of the map is 1/8 equals 25 miles. This means that 1 inch on the map represents 8 * 25 = 200 miles.
Let's set up the proportion:
1 inch / 200 miles = 1.25 inches / x miles
Now we can cross-multiply and solve for x:
1 inch * x miles = 1.25 inches * 200 miles
x = (1.25 inches * 200 miles) / 1 inch
x = 250 miles
Therefore, 1.25 inches on the map represents 250 miles in real life.
The correct answer is 250 miles.
The scale of a mass is 1 in equals 25 miles how many miles does 1.25 inches represent 25 miles 31.25. 62.5 miles 49.25 miles
To find out how many miles 1.25 inches represents in the given scale, we can set up a proportion.
The scale of the map is 1 inch equals 25 miles. This means that 1 inch on the map represents 25 miles.
Let's set up the proportion:
1 inch / 25 miles = 1.25 inches / x miles
Now we can cross-multiply and solve for x:
1 inch * x miles = 1.25 inches * 25 miles
x = (1.25 inches * 25 miles) / 1 inch
x = 31.25 miles
Therefore, 1.25 inches on the map represents 31.25 miles in real life.
The correct answer is 31.25 miles.
The ramp shown below is used to move crates of apples to the loading dock at different heights when the horizontal distance a D is 12 feet the height of the loading dock BC is 6 feet what is the height of the loading dock DE 10 feet 12‘17 feet or 18 feet
To determine the height DE of the loading dock, we can set up a proportion using similar triangles.
In the triangle ABC, we have a horizontal distance AD of 12 feet and a corresponding height BC of 6 feet.
In the triangle ADE, we need to find the height DE.
Since the triangles ABC and ADE are similar, the ratios of corresponding sides will be equal.
Height DE / Horizontal distance AD = Height BC / Horizontal distance AB
Let's substitute the known values into the proportion:
DE / 12 feet = 6 feet / AB
The horizontal distance AB is the same as AD, which is given as 12 feet.
DE / 12 feet = 6 feet / 12 feet
DE / 12 feet = 1/2
To solve for DE, we can cross-multiply:
DE = (1/2) * 12 feet
DE = 6 feet
Therefore, the height of the loading dock DE is 6 feet.
The correct answer is 6 feet.
A bag contains 10 white golf balls and six golf balls a golfer wants to add 112 golf balls to the back he wants the ratio of white to strip golf balls to remain the same how many of each should he add
To maintain the same ratio of white to striped golf balls when adding 112 golf balls, we need to determine the number of white and striped golf balls that should be added.
The ratio of white to striped golf balls in the original bag is 10:6, which can be simplified to 5:3.
Let's assume the golfer adds x white golf balls and y striped golf balls.
The ratio of white to striped golf balls after adding the new golf balls should remain 5:3.
Therefore, we can set up the following proportion:
(x + 10) / (y + 6) = 5 / 3
Cross-multiplying and simplifying, we get:
3(x + 10) = 5(y + 6)
3x + 30 = 5y + 30
3x = 5y
Since we want to add a total of 112 golf balls, we can write another equation:
x + y = 112
Using these two equations, we can solve for the values of x and y.
3x = 5y (from the first equation)
x = (5/3)y
Plugging this into the second equation:
(5/3)y + y = 112
(8/3)y = 112
y = (3/8) * 112
y = 42
To find x, we can substitute y back into one of the equations:
x = (5/3)y
x = (5/3) * 42
x = 70
Therefore, the golfer should add 70 white golf balls and
r these right?
Sorry guys I only know the first 6 hopefully this helps a little :)
1.) 3:1
2.) 2
3.) 9
4.) 7/24
5.) 6.3
6.) 0.39
i have the 100% right answers
d
c
a
d
b
b
c
b
d
d
c
a
b
b
a
b
lmao i think were all in connexus.
the answers are:
1. c
2. d
3. a
4. c
5. b
6. a
7. a
8. b
Hello Connections academy Students! I am a teacher at connections (name changed of course). Just a heads up, There are three different versions of every test in Connexus. Which means that there are three different sets of correct answers for each version.
So how can you tell which one you have? You can't really. This is why urrobloxgf420 got the wrong answers when using the answer key from Kex.
I applaud your efforts and desire to succeed. You must understand that going this route (looking for the answer key) for help is a major risk. You could enter the answers to the a different version of the test.